Codeforces Round #260 (Div. 2) A
Description
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.
Please, check the guess of Alex. You are given descriptions of n laptops. Determine whether two described above laptops exist.
The first line contains an integer n (1 ≤ n ≤ 105) — the number of laptops.
Next n lines contain two integers each, ai and bi (1 ≤ ai, bi ≤ n), where ai is the price of the i-th laptop, and bi is the number that represents the quality of the i-th laptop (the larger the number is, the higher is the quality).
All ai are distinct. All bi are distinct.
If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes).
2
1 2
2 1
Happy Alex
题意:问你是价格高才质量高,还是价格低质量高
解法:排序,如果发现价格高但质量比之前的低,就输出Poor Alex,否则就是Happy Alex
#include<bits/stdc++.h>
using namespace std;
class P
{
public:
int n,m;
};
bool cmd(P x,P y)
{
return x.n<y.n;
}
int main()
{
P x[100005];
int n;
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>x[i].m>>x[i].n;
}
sort(x+1,x+1+n,cmd);
for(int i=2;i<=n;i++)
{
if(x[i].m<x[i-1].m)
{
cout<<"Happy Alex"<<endl;
return 0;
}
}
cout<<"Poor Alex"<<endl;
return 0;
}
Codeforces Round #260 (Div. 2) A的更多相关文章
- DP Codeforces Round #260 (Div. 1) A. Boredom
题目传送门 /* 题意:选择a[k]然后a[k]-1和a[k]+1的全部删除,得到点数a[k],问最大点数 DP:状态转移方程:dp[i] = max (dp[i-1], dp[i-2] + (ll) ...
- 递推DP Codeforces Round #260 (Div. 1) A. Boredom
题目传送门 /* DP:从1到最大值,dp[i][1/0] 选或不选,递推更新最大值 */ #include <cstdio> #include <algorithm> #in ...
- Codeforces Round #260 (Div. 2)AB
http://codeforces.com/contest/456/problem/A A. Laptops time limit per test 1 second memory limit per ...
- Codeforces Round #260 (Div. 1) D. Serega and Fun 分块
D. Serega and Fun Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/455/pro ...
- Codeforces Round #260 (Div. 1) C. Civilization 并查集,直径
C. Civilization Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/455/probl ...
- Codeforces Round #260 (Div. 1) A - Boredom DP
A. Boredom Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/455/problem/A ...
- Codeforces Round #260 (Div. 1) A. Boredom (简单dp)
题目链接:http://codeforces.com/problemset/problem/455/A 给你n个数,要是其中取一个大小为x的数,那x+1和x-1都不能取了,问你最后取完最大的和是多少. ...
- Codeforces Round #260 (Div. 1) 455 A. Boredom (DP)
题目链接:http://codeforces.com/problemset/problem/455/A A. Boredom time limit per test 1 second memory l ...
- Codeforces Round #260 (Div. 2)
A. Laptops 题目意思: 给定n台电脑,第i台电脑的价格是ai ,质量是bi ,问是否存在一台电脑价格比某台电脑价格底,但质量确比某台电脑的质量高,即是否存在ai < aj 且 bi & ...
- Codeforces Round #260 (Div. 2) C
Description Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. On ...
随机推荐
- Python和Ruby开发中源文件中文注释乱码的解决方法(Eclipse和Aptana Studio3均适用)
Eclipse的设置(Aptana Studio3与Eclipse基本完全相同,此处略) window->preferences->general->editors->text ...
- HDU 4899 Hero meet devil(状压DP)(2014 Multi-University Training Contest 4)
Problem Description There is an old country and the king fell in love with a devil. The devil always ...
- paper 89:视频图像去模糊常用处理方法
随着“平安城市”的广泛建设,各大城市已经建有大量的视频监控系统,虽然监控系统己经广泛地存在于银行.商场.车站和交通路口等公共场所,但是在公安工作中,由于设备或者其他条件的限制,案情发生后的图像回放都存 ...
- paper 45:latex的使用
本教程面向对LaTeX完全无认知无基础的新人. 旨在让新人能够用最简单快捷的方式,轻松入门,能够迅速使用LaTeX完成基本的文本编辑. 尤其旨在破除部分新人对LaTeX在传闻中难以学习的恐惧感. 在入 ...
- 夺命雷公狗---Thinkphp----9之中间层的创建,防止跨目录访问
我们创建一个CommonController.class.php的中间层,让后让别的控制器都直接继承CommonController这个控制器即可决解跨目录访问的问题, <?php namesp ...
- [sinatra] Sinatra再入门
原文URL:http://www.rubycc.com/bbs/topic_detail/86 1.基础代码app.rb require 'rubygems' require 'sinatra/bas ...
- tomcat支持的websocket服务
首发:个人博客 在tomcat7之后的版本,写个websocket服务程序非常容易——如以下代码所示,当客户端建立了一个连接并发送了一些什么内容到服务器,服务器将每隔两秒返回一个字符串“world”. ...
- MySQL rename database如何做?
虽然MySQL里面有rename database的语法,但是只是在5.1.7 to 5.1.23提供的,其他版本并没有,要想做rename操作该如何做呢?percona提供了一个shell #!/b ...
- 坑爹的VS2012
2.2.2.如果卸载 Visual Studio 2010 Service Pack 1,则必须先重新安装 Visual Studio 2010,然后才能再次安装 SP1 如果卸载 Visual St ...
- MySQL Replication 优化和技巧、常见故障解决方法
MySQL 主从同步错误(error)解决(转) sql_slave_skip_counter参数 附: 一些错误信息的处理,主从服务器上的命令,及状态信息. 在从服务器上使用show slave s ...