题意:

  就是求最小割点

解析:

  正向一遍spfa 反向一遍spfa  然后遍历每一条边,对于当前边 如果dis1[u] + dis2[v] + 1 <= k 那么就把这条边加入到网络流图中,

  每个点拆点 边权为1

  跑最大流即可

代码还是改的那一题。。。

  

#include <iostream>
#include <cstring>
#include <cstdio>
#include <queue>
#include <cmath>
#include <vector>
#define mem(a,b) memset(a,b,sizeof(a))
using namespace std;
const int maxn = 1e3 + , INF = 0xfffffff, maxm = ;
typedef long long LL;
int n,m, cnt, s, t, k;
int head[maxn], d[maxn], vis[maxn], dis1[maxn], dis2[maxn], head1[maxn], cur[maxn];
int from[maxm], to[maxm];
int bz[][], way[][]; struct edge
{
int u, v, c, next;
}Edge[maxm << ]; void add_(int u, int v, int c)
{
Edge[cnt].u = u;
Edge[cnt].v = v;
Edge[cnt].c = c;
Edge[cnt].next = head1[u];
head1[u] = cnt++;
} void add_edge(int u, int v, int c)
{
add_(u, v, c);
add_(v, u, );
} bool bfs()
{
mem(d, );
queue<int> Q;
Q.push(s);
d[s] = ;
while(!Q.empty())
{
int u = Q.front(); Q.pop();
for(int i = head1[u]; i != -; i = Edge[i].next)
{
edge e = Edge[i];
if(!d[e.v] && e.c > )
{
d[e.v] = d[u] + ;
Q.push(e.v);
if(e.v == t) return ;
}
}
}
return d[t] != ;
} int dfs(int u, int cap)
{
int ret = ;
if(u == t || cap == )
return cap;
for(int &i = cur[u]; i != -; i = Edge[i].next)
{
edge e = Edge[i];
if(d[e.v] == d[u] + && e.c > )
{
int V = dfs(e.v, min(e.c, cap));
Edge[i].c -= V;
Edge[i ^ ].c += V;
ret += V;
cap -= V;
if(cap == ) break;
}
}
if(cap > ) d[u] = -;
return ret;
} int Dinic()
{
int ans = ;
while(bfs())
{
memcpy(cur, head1, sizeof(head1));
ans += dfs(s, INF);
}
return ans;
} struct node
{
int u, v, w, next;
}Node[maxn * ]; void add(int u,int v,int w,int i)
{
Node[i].u = u;
Node[i].v = v;
Node[i].w = w;
Node[i].next = head[u];
head[u] = i;
}
void spfa(int s)
{
for(int i = ; i < maxn; i++) d[i] = INF;
queue<int> Q;
d[s] = ;
mem(vis,);
Q.push(s);
vis[s] = ;
while(!Q.empty())
{
int u = Q.front();Q.pop();
vis[u] = ;
for(int i=head[u]; i!=-; i=Node[i].next)
{
node e = Node[i];
if(d[e.v] > d[u] + e.w)
{
d[e.v] = d[u] + e.w;
if(!vis[e.v])
{
Q.push(e.v);
vis[e.v] = ;
}
}
} }
} int main()
{
int T,A,B;
while(~scanf("%d%d%d", &n, &m, &k))
{
if(n==&&m==&&k==)
break;
mem(way, );
mem(bz, );
mem(Node,);
mem(head,-);
mem(head1, -);
cnt = ;
for(int i=; i<m; i++)
{
scanf("%d%d",&from[i],&to[i]);
if(!bz[from[i]][to[i]])
{
add(from[i],to[i],,i), bz[from[i]][to[i]] = ;
way[from[i]][to[i]] = ;
}
}
s = , t = n;
spfa(s);
mem(Node,);
for(int i=; i<=n; i++)
dis1[i] = d[i];
mem(head,-);
for(int i=; i<m; i++)
add(to[i],from[i],,i);
spfa(t);
for(int i=; i<=n; i++)
dis2[i] = d[i];
mem(bz, );
s = + n, t = n;
for(int i = ; i <= n; i++)
{
for(int j = ; j <= n; j++)
{
if(way[i][j] && dis1[i] + dis2[j] + <= k)
add_edge(i, j, INF);
}
add_edge(i, i + n, );
} printf("%d\n",Dinic());
}
return ;
}

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