9. Palindrome Number(判断整型数字是否是回文，直接暴力即可)

Determine whether an integer is a palindrome. Do this without extra space.

 class Solution:
     def isPalindrome(self, x):
         """
         :type x: int
         :rtype: bool
         """
         x =str(x)

         for i in range(int(len(x)/2)+1):
             if(x[i]!=x[len(x)-i-1]):
                 return False

         return True