HDU 6373 Pinball
Pinball
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)
Total Submission(s): 131 Accepted Submission(s): 55
It's guarantee that the ball will not reach the slope or ground or Y-axis with a distance of less than 1 from the origin. And the ball is elastic collision without energy loss. Gravity acceleration $g = 9.8 m/s^2$.
The first line of each test case contains four integers a, b, x, y (1 $\le$ a, b, -x, y $\le$ 100), indicate that the slope will pass through the point(-a, b), the initial position of the ball is (x, y).
It's guarantee that the answer will not exceed 50.
5 1 -5 3
Statistic | Submit | Discuss | Note
#include <iostream>
#include <string>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <vector>
#include <queue>
#include <deque>
#include <map>
#define range(i,a,b) for(auto i=a;i<=b;++i)
#define LL long long
#define ULL unsigned long long
#define elif else if
#define itrange(i,a,b) for(auto i=a;i!=b;++i)
#define rerange(i,a,b) for(auto i=a;i>=b;--i)
#define fill(arr,tmp) memset(arr,tmp,sizeof(arr))
#define IOS ios::sync_with_stdio(false);cin.tie(0)
using namespace std;
int t,a,b,x,y;
const double g=9.8;
void init(){
scanf("%d",&t);
}
void solve(){
while(t--){
scanf("%d%d%d%d",&a,&b,&x,&y);
double SIN=b*1.0/sqrt(a*a+b*b);
double h=y+b*x*1.0/a,l=h*SIN+sqrt(x*x*(+b*b*1.0/(a*a)));
double TR=sqrt(*l/(g*SIN)),T=sqrt(*h/g);
int cnt=int(TR/T),ans=(cnt+)>>;
cout<<ans<<endl;
}
}
int main() {
init();
solve();
return ;
}
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