AC Milan VS Juventus(模拟)
AC Milan VS Juventus
Time Limit: 3000/1000MS (Java/Others) Memory Limit: 65535/65535KB (Java/Others)
Kennethsnow and Hlwt both love football.
One day, Kennethsnow wants to review the match in 20032003 between AC Milan and Juventus for the Championship Cup. But before the penalty shootout. he fell asleep.
The next day, he asked Hlwt for the result. Hlwt said that it scored aa:bb in the penalty shootout.
Kennethsnow had some doubt about what Hlwt said because Hlwt is a fan of Juventus but Kennethsnow loves AC Milan.
So he wanted to know whether the result can be a legal result of a penalty shootout. If it can be, output Yes, otherwise output No.
The rule of penalty shootout is as follows:
There will be 55 turns, in each turn, 22 teams each should take a penalty shoot. If goal, the team get 11 point. After each shoot, if the winner can be confirmed(i.e: no matter what happened after this shoot, the winner will not change), the match end immediately.
If after 55 turns the 22 teams score the same point. A new turn will be added, until that one team get a point and the other not in a turn.
Before the penalty shootout begins, the chief referee will decide which team will take the shoot first, and afterwards, two teams will take shoot one after the other. Since Kennethsnow fell asleep last night, he had no idea whether AC Milan or Juventus took the first shoot.
Input
The only line contains 22 integers aa, bb. Means the result that Hlwt said.
0≤a,b≤100≤a,b≤10
Output
Output a string Yes or No, means whether the result is legal.
Sample input and output
| Sample Input | Sample Output |
|---|---|
3 2 |
Yes |
2 5 |
No |
Hint
The Sample 11 is the actual result of the match in 20032003.
The Sample 22, when it is 22:44 after 44 turns, AC Milan can score at most 11 point in the next turn. So Juventus has win when it is 22:44. So the result cannot be 22:55.
This story happened in a parallel universe. In this world where we live, kennethsnow is a fan of Real Madrid.
题解:两个队投球,进了得1分,当一个队必胜的时候可以不用打了;现在给出得分判断是否合理;
代码:
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
bool work(int a, int b){
if(a == b)
return false;
if(a > || b > ){
if(abs(a - b) == )
return true;
else
return false;
}
if(a == || b == ){
if(b < || a < )
return false;
else
return true;
}
if(a == || b == ){
if(a == || b == )
return false;
else
return true;
}
if(a == || b == ){
return true;
}
return true;
}
int main(){
int a, b;
while(~scanf("%d%d", &a, &b)){
if(work(a, b))
puts("Yes");
else
puts("No");
}
return ;
}
AC Milan VS Juventus(模拟)的更多相关文章
- UESTC 1034 AC Milan VS Juventus 分情况讨论
AC Milan VS Juventus Time Limit: 3000/1000MS (Java/Others) Memory Limit: 65535/65535KB (Java/Oth ...
- cdoj第13th校赛初赛A - AC Milan VS Juventus 【枚举】
http://acm.uestc.edu.cn/#/contest/show/54 A - AC Milan VS Juventus Time Limit: 3000/1000MS (Java/Oth ...
- noi.ac NOI挑战营模拟赛1-5
注:因为博主是个每次考试都爆零垫底的菜鸡,所以此篇博客很有可能咕咕咕 (指只贴AC代码不写题解的......如果我真的不会做的话,就不能怪我了qwqwq) Day1 T1 swap 23pts 从一个 ...
- [NOI.AC]NOI2019省选模拟赛 第二场
传送门 Solution A. 一共有\(T\)组数据 每次询问你\([l,r]\)中有多少个数能被他的所有数位整除(如果数位中含有\(0\)忽略掉) 数位dp,咕咕咕 B. 题面略 考虑一个个只有两 ...
- noi.ac 邀请赛1 By cellur925
A. array 考场:上来就想暴力,首先第一个子任务肯定没问题,怎么搞都行.然后第二个子任务用个数组记下新修的值就行了.第三个子任务用一下等差数列求和公式帮助求解,每次都重新算(因为每次改变全部元素 ...
- Daily record-September
September11. I feel much more reassured when I've been for a health check. 体检之后我感到放心多了.2. The diseas ...
- noip2016题解汇总
[uoj#260]玩具谜题 传送门 http://uoj.ac/problem/260 分析 模拟. int n,m; int dir[N]; char nam[N][L]; int a[M],s[M ...
- 字典树trie的学习与练习题
博客详解: http://www.cnblogs.com/huangxincheng/archive/2012/11/25/2788268.html http://eriol.iteye.com/bl ...
- SCAU 07校赛 10317 Fans of Footbal Teams
10317 Fans of Footbal Teams 时间限制:1000MS 内存限制:65535K 题型: 编程题 语言: 无限制 Description Two famous footba ...
随机推荐
- BoneCP学习笔记
什么是BoneCP BoneCP 是一个快速.免费而且开源的java数据库连接池(JDBC Pool)管理工具库.如果你曾经使用过C3P0或者DBCP,那你肯定知道上面这句话的意思:如果你没用过这些, ...
- HDU 2689 sort it - from lanshui_Yang
Problem Description You want to processe a sequence of n distinct integers by swapping two adjacent ...
- Android菜鸟的成长笔记(28)——Google官方对Andoird 2.x提供的ActionBar支持
在Google官方Android设计指南中(链接:http://www.apkbus.com/design/get-started/ui-overview.html)有一个新特性就是自我标识,也就是宣 ...
- webform开发经验(一):Asp.Net获取Checkbox选中的值
webform中获取repeat控件列表下的checkbox选中的值: 码农上代码: public static string getSelectedIDs(Repeater Rpt_) { stri ...
- [QT]QT概述
QT概述 基于C++的GUI开发框架,跨平台.Qt 是一个用于桌面系统和嵌入式开发的跨平台应用程序框架. QT是挪威TROLLTECH公司开发的跨平台C++工具,在UNIX下非常出名:他的宗旨是“一次 ...
- 关于页面刷新或者调用方法事获取不到元素信息或者出现缺少对象错误的换位思考setTimeout的使用
这两天客户的需求不能定下来,做闲人好长时间了,不如来整理下最近碰到的一些个小麻烦. 正题: 场景一. 最近在开发的过程中使用到了百度的富客户端文本编辑器(ueditor)---这是一款功能很强大的文本 ...
- C# 获取当前路径
// 获取程序的基目录.System.AppDomain.CurrentDomain.BaseDirectory F:\广告编辑系统新\taxi_edit\taxi_form\bin\Debug\ ...
- 一个支持实时预览的在线 Markdown 编辑器 - Markdoc
最近组内需要为一些项目和系统写文档,发表在公司内的文档平台上,这个平台并不支持markdown,所以打算做一个在线markdown编辑器,支持实时预览,并且可以很容易的迁移发表到公司文档平台上,所以就 ...
- 函数:内嵌函数和闭包 - 零基础入门学习Python020
函数:内嵌函数和闭包 让编程改变世界 Change the world by program 内嵌函数和闭包 接下来这两节课我们谈的话题可能会"比较高级",所以如果是零基础的朋友, ...
- Java笔记--java一行一行写入或读取数据
转自 Ruthless java一行一行写入或读取数据 链接:http://www.cnblogs.com/linjiqin/archive/2011/03/23/1992250.html 假如E:/ ...