hdoj 1532 Drainage Ditches(最大网络流)

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1532

思路分析：问题为最大网络流问题，给定一个有向图，需要求解该有向图的最大网络流，使用EdmondsKarp算法求解；

需要注意输入的边中可能有重边的存在；

代码如下：

#include <queue>
#include <vector>
#include <cstdio>
#include <climits>
#include <cstring>
#include <iostream>
using namespace std;

const int MAX_N =  + ;
int cap[MAX_N][MAX_N], flow[MAX_N][MAX_N];
int a[MAX_N], p[MAX_N];

inline int Min(int a, int b) { return a < b ? a : b; }
int EdmondsKarp(int ver_num)
{
    queue<int> q;
    int max_flow = ;

    memset(flow, , sizeof(flow));
    for (;;)
    {
        memset(a, , sizeof(a));
        a[] = INT_MAX;
        q.push();
        while (!q.empty())
        {
            int u = q.front();
            q.pop();
            for (int v = ; v <= ver_num; ++v)
            {
                if (!a[v] && cap[u][v] > flow[u][v])
                {
                    p[v] = u;
                    q.push(v);
                    a[v] = Min(a[u], cap[u][v] - flow[u][v]);
                }
            }
        }
        if (a[ver_num] == )  break;
        for (int u = ver_num; u != ; u = p[u])
        {
            flow[p[u]][u] += a[ver_num];
            flow[u][p[u]] -= a[ver_num];
        }
        max_flow += a[ver_num];
    }
    return max_flow;
}

int main()
{
    int road_num, ver_num;

    while (scanf("%d %d", &road_num, &ver_num) != EOF)
    {
        int ver_1, ver_2, capa;

        memset(cap, , sizeof(cap));
        for (int i = ; i < road_num; ++i)
        {
            scanf("%d %d %d", &ver_1, &ver_2, &capa);
            cap[ver_1][ver_2] += capa;
        }
        int ans = EdmondsKarp(ver_num);
        printf("%d\n", ans);
    }
    return ;
}