Codeforces Round #346 (Div. 2) B Qualifying Contest
B. Qualifying Contest
题目链接http://codeforces.com/contest/659/problem/B
Description
Very soon Berland will hold a School Team Programming Olympiad. From each of the m Berland regions a team of two people is invited to participate in the olympiad. The qualifying contest to form teams was held and it was attended by n Berland students. There were at least two schoolboys participating from each of the m regions of Berland. The result of each of the participants of the qualifying competition is an integer score from 0 to 800 inclusive.
The team of each region is formed from two such members of the qualifying competition of the region, that none of them can be replaced by a schoolboy of the same region, not included in the team and who received a greater number of points. There may be a situation where a team of some region can not be formed uniquely, that is, there is more than one school team that meets the properties described above. In this case, the region needs to undertake an additional contest. The two teams in the region are considered to be different if there is at least one schoolboy who is included in one team and is not included in the other team. It is guaranteed that for each region at least two its representatives participated in the qualifying contest.
Your task is, given the results of the qualifying competition, to identify the team from each region, or to announce that in this region its formation requires additional contests.
Input
The first line of the input contains two integers n and m (2 ≤ n ≤ 100 000, 1 ≤ m ≤ 10 000, n ≥ 2m) — the number of participants of the qualifying contest and the number of regions in Berland.
Next n lines contain the description of the participants of the qualifying contest in the following format: Surname (a string of length from 1 to 10 characters and consisting of large and small English letters), region number (integer from 1 to m) and the number of points scored by the participant (integer from 0 to 800, inclusive).
It is guaranteed that all surnames of all the participants are distinct and at least two people participated from each of the m regions. The surnames that only differ in letter cases, should be considered distinct.
Output
Print m lines. On the i-th line print the team of the i-th region — the surnames of the two team members in an arbitrary order, or a single character "?" (without the quotes) if you need to spend further qualifying contests in the region.
Sample Input
5 2
Ivanov 1 763
Andreev 2 800
Petrov 1 595
Sidorov 1 790
Semenov 2 503
Sample Output
Sidorov Ivanov
Andreev Semenov
题意:
给你n个人m只队伍。问能否每对确定得分最高的两个人。能则输出人名,不能则输出“?”。
题解:
只需开m个数组,鉴于太大,可使用vector。再对每个队伍排序。如只有两个人,输出这两个人。如果超过两个人如果第二个人和第三个人得分相同则输出“?”,否则输出前两个人人名。
代码:
#include<bits/stdc++.h>
using namespace std;
struct node
{
char name[15];
int dui;
int fen;
};
bool cmp(node s1,node s2)
{
return s1.fen > s2.fen;
}
vector <node> s[100100];
int main()
{
int n,m;
scanf("%d%d",&n,&m);
node temp;
for (int i = 1; i <= n; i++)
{
scanf("%s %d %d",temp.name,&temp.dui,&temp.fen);
s[temp.dui].push_back(temp);
}
for (int i = 1; i <= m; i++)
{
sort(s[i].begin(),s[i].end(),cmp);
if (s[i].size()==2)
printf("%s %s\n",s[i][0].name,s[i][1].name);
else {
if (s[i][1].fen == s[i][2].fen)
printf("?\n");
else
printf("%s %s\n",s[i][0].name,s[i][1].name);
}
}
}
Codeforces Round #346 (Div. 2) B Qualifying Contest的更多相关文章
- Codeforces Round #346 (Div. 2) B. Qualifying Contest 水题
B. Qualifying Contest 题目连接: http://www.codeforces.com/contest/659/problem/B Description Very soon Be ...
- Codeforces Round #346 (Div. 2)---E. New Reform--- 并查集(或连通图)
Codeforces Round #346 (Div. 2)---E. New Reform E. New Reform time limit per test 1 second memory lim ...
- Codeforces Round #346 (Div. 2) B题
B. Qualifying Contest Very soon Berland will hold a School Team Programming Olympiad. From each of t ...
- Codeforces Round #346 (Div. 2) A Round-House
A. Round House 题目链接http://codeforces.com/contest/659/problem/A Description Vasya lives in a round bu ...
- Codeforces Round #346 (Div. 2) A. Round House 水题
A. Round House 题目连接: http://www.codeforces.com/contest/659/problem/A Description Vasya lives in a ro ...
- Codeforces Round #346 (Div. 2) D Bicycle Race
D. Bicycle Race 题目链接http://codeforces.com/contest/659/problem/D Description Maria participates in a ...
- Codeforces Round #346 (Div. 2) C Tanya and Toys
C. Tanya and Toys 题目链接http://codeforces.com/contest/659/problem/C Description In Berland recently a ...
- Codeforces Round #346 (Div. 2) G. Fence Divercity dp
G. Fence Divercity 题目连接: http://www.codeforces.com/contest/659/problem/G Description Long ago, Vasil ...
- Codeforces Round #346 (Div. 2) F. Polycarp and Hay 并查集 bfs
F. Polycarp and Hay 题目连接: http://www.codeforces.com/contest/659/problem/F Description The farmer Pol ...
随机推荐
- Linux centOS本地DNS安装
centOS本地DNS安装 在centOS里最常用的DNS服务工具应该是bind了.下面就以bind为例做一个DNS服务. 首先查看bind 是否已经安装 Rpm -qa | gerp bind 如果 ...
- Organic Solar Cells - Theory and Practice
renewable engergy: Wind solar Tidal Wave Ocean Bio Etc. How much energy we gonna need as following y ...
- mongDB
MongoDB[第一篇]MongodDB初识 NoSQL介绍 一.NoSQL简介 NoSQL,全称是”Not Only Sql”,指的是非关系型的数据库. 非关系型数据库主要有这些特点:非关系型的 ...
- 解决Eclipse一直loading workbench无法启动的问题
不知怎地,Eclipse始终停留在Loading workbench状态.反复重启,状态依旧.尝试解决. 停止时显示的状态:”Loading workbench”,看来和这个workbench插件有关 ...
- CMake学习
CMake学习 本篇分享一下有关CMake的一些学习心得以及相关使用. 作者:AlphaGL.版权所有,欢迎保留原文链接进行转载 :) 本文目录如下: 1.CMake介绍 2.CMake安装与使用 2 ...
- MP4视频编码器
用 HTML5 播放视频,最流行的视频格式非 MP4莫属, 所有最新浏览器都支持; MP4 带有 H.264 视频编码和 AAC 音频编码的 MPEG 4 文件: 以前做过一个把其它编码格式的视频转成 ...
- C语言递归回溯法迷宫求解
本例将随机产生一个10*10的迷宫输出后,在下面输出此迷宫的解法. 解法为从坐标(1,1)处进入,从(8,8,)出去,优先线路为先右后下再上最后为左. 不少人求解此题时运用的栈的相关知识,本例寻找线路 ...
- 黄聪:VPS服务器好备份工具配置
- python3的文件读写模式
任何一种语言,文件的读写都是非常常见的.python的文件读写非常简单,仅仅一个函数open(file也可以,但是我不常用). 先看看官网的解释: open(file, mode='r', buffe ...
- git的一些疑难点
一 .git reset,git revert,git checkout的区别和联系 主要参考:http://www.cnblogs.com/houpeiyong/p/5890748.html git ...