IITWPC4F - Gopu and the Grid Problem

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Gopu is interested in the integer co-ordinates of the X-Y plane (0<=x,y<=100000). Each integer coordinate contain a lamp, initially all the lamps are in off mode. Flipping a lamp means switching it on if it is in off mode and vice versa. Maggu will ask gopu 3 type of queries.

 

Type 1:  x l r,  meaning: flip all the lamps whose x-coordinate are between l and r (both inclusive) irrespective of the y coordinate.

 

Type 2:  y l r, meaning: flip all the lamps whose y-coordinate are between l and r (both inclusive) irrespective of the x coordinate.

 

Type 3: q x y X Y, meaning: count the number of lamps which are in ‘on mode’(say this number be A) and ‘off mode’ (say this number  be B) in the region where x-coordinate is between x and X(both inclusive) and y-coordinate is between y and Y(both inclusive).

Input

First line contains Q-number of queries that maggu will ask to gopu. (Q <= 10^5)

 

Then there will be Q lines each containing a query of one of the three type described above.

Output

For each query of 3rd type you need to output a line containing one integer A.

Example

Input:

3

x 0 1

y 1 2

q 0 0 2 2

Output: 
 4

线段树

题目链接:http://www.spoj.com/problems/IITWPC4F/en/

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<iostream>
#include<cstdio>
#include<cmath>
#include<string>
#include<queue>
#include<algorithm>
#include<stack>
#include<cstring>
#include<vector>
#include<list>
#include<set>
#include<map>
using namespace std;
#define ll long long
#define pi (4*atan(1.0))
#define mk make_pair
#define eps 1e-7
#define bug(x) cout<<"bug"<<x<<endl;
const int N=5e5+,M=1e6+,inf=;
const ll INF=1e18+,mod=; /// 数组大小
struct SGT
{
int tree[N],lazy[N];
void pushup(int pos)
{
tree[pos]=tree[pos<<|]+tree[pos<<];
}
void pushdown(int pos,int l,int r)
{
if(lazy[pos])
{
lazy[pos<<]^=;
lazy[pos<<|]^=;
int mid=(l+r)>>;
tree[pos<<]=(mid-l+)-tree[pos<<];
tree[pos<<|]=(r-mid)-tree[pos<<|];
lazy[pos]=;
}
}
void build(int l,int r,int pos)
{
tree[pos]=lazy[pos]=;
if(l==r)return;
int mid=(l+r)>>;
build(l,mid,pos<<);
build(mid+,r,pos<<|);
}
void update(int L,int R,int l,int r,int pos)
{
if(L<=l&&r<=R)
{
lazy[pos]^=;
tree[pos]=(r-l+)-tree[pos];
return;
}
pushdown(pos,l,r);
int mid=(l+r)>>;
if(L<=mid)
update(L,R,l,mid,pos<<);
if(R>mid)
update(L,R,mid+,r,pos<<|);
pushup(pos);
}
int query(int L,int R,int l,int r,int pos)
{
if(L<=l&&r<=R)
return tree[pos];
pushdown(pos,l,r);
int mid=(l+r)>>;
int ans=;
if(L<=mid)
ans+=query(L,R,l,mid,pos<<);
if(R>mid)
ans+=query(L,R,mid+,r,pos<<|);
return ans;
}
};
SGT x,y;
char ch[];
int main()
{
int q;
int n=;
while(~scanf("%d",&q))
{
x.build(,n,);
y.build(,n,);
while(q--)
{
int l,r;
scanf("%s%d%d",ch,&l,&r);
//if(l<r)swap(l,r);
if(ch[]=='x')
x.update(l+,r+,,n,);
else if(ch[]=='y')
y.update(l+,r+,,n,);
else
{
int L,R;
scanf("%d%d",&L,&R);
//if(L<R)swap(L,R);
int xx=x.query(l+,L+,,n,);
int yy=y.query(r+,R+,,n,);
ll ans=;
ans+=1LL*xx*(R-r+);
ans+=1LL*yy*(L-l+);
ans-=2LL*xx*yy;
printf("%lld\n",ans);
}
}
}
return ;
}

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