解法一:Brute-force

 int strStr(string haystack, string needle)
{
int m = haystack.size();
int n = needle.size();
if (!n)
return ;
for (int i = ; i < m - n + ; ++i) {
int k = i, j = ;
while (j < n) {
if (needle[j] == haystack[k]) {
j++;
k++;
} else {
break;
}
}
if (j == n)
return i;
}
return -;
}

解法二:KMP

 vector<int> GetNext(const string& T)
{
int len = T.size();
vector<int> next(len, );
for (int i = , k = ; i < len;) {
if (T[i] == T[k])
next[i++] = ++k;
else if (k)
k = next[k - ];
else
next[i++] = ;
}
return next;
} int strStr(string haystack, string needle)
{
int m = haystack.size();
int n = needle.size();
if (n == )
return ; vector<int> next = GetNext(needle);
for (int i = , j = ; i < m;) {
if (haystack[i] == needle[j]) {
i++;
j++;
}
if (j == n)
return i - n;
if (i < m && haystack[i] != needle[j]) {
if (j)
j = next[j - ];
else
i++;
}
}
return -;
}

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