poj1080 dp

 //Accepted    200 KB    0 ms
 //dp
 //dp[i][j]表示s1用前i个,s2用前j个字符能得到的最大分数
 //dp[i][j]=max(dp[i-1][j]+score[s1[i-1]]['-'],
 //             dp[i][j-1]+score[['-'][s2[j-1]],
 //             dp[i-1][j-1]+score[s1[i-1]][s2[j-1]])
 //注意初始化
 //dp[0][0]=0;
 //dp[0][i]=dp[0][i-1]+score['-'][s2[i-1]]
 //dp[i][0]=dp[i-1][0]+score[s1[i-1]]['-']
 //还要初始化dp[i][j]=-inf;
 #include <cstdio>
 #include <cstring>
 #include <iostream>
 using namespace std;
 ;
 ;
 int dp[imax_n][imax_n];
 int n1,n2;
 char s1[imax_n];
 char s2[imax_n];
 int getScore(char ch1,char ch2)
 {
     ;
     ;
     ;
     ;
     ;
     if (ch1=='C')
     {
         ;
         ;
         ;
         ;
     }
     if (ch1=='G')
     {
         ;
         ;
         ;
         ;
     }
     if (ch1=='T')
     {
         ;
         ;
         ;
         ;
     }
     if (ch1=='-')
     {
         ;
         ;
         ;
         ;
     }
 }
 void Dp()
 {
     //memset(dp,0,sizeof(dp));
     dp[][]=;
     ;i<=n1;i++)
     dp[i][]=dp[i-][]+getScore(s1[i-],'-');
     ;i<=n2;i++)
     dp[][i]=dp[][i-]+getScore(]);
     ;i<=n1;i++)
     {
         ;j<=n2;j++)
         {
             dp[i][j]=inf;
             ]+getScore(])>dp[i][j])
             dp[i][j]=dp[i][j-]+getScore(]);
             ][j]+getScore(s1[i-],'-'))
             dp[i][j]=dp[i-][j]+getScore(s1[i-],'-');
             ][j-]+getScore(s1[i-],s2[j-]))
             dp[i][j]=dp[i-][j-]+getScore(s1[i-],s2[j-]);
         }
     }
     printf("%d\n",dp[n1][n2]);
 }
 int main()
 {
     int T;
     scanf("%d",&T);
     while (T--)
     {
         scanf("%d",&n1);
         scanf("%s",s1);
         scanf("%d",&n2);
         scanf("%s",s2);
         Dp();
     }
     ;
 }