Python [Leetcode 350]Intersection of Two Arrays II

题目描述：

Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].

Note:

• Each element in the result should appear as many times as it shows in both arrays.
• The result can be in any order.

解题思路：

排序，对比

代码如下：

class Solution(object):
    def intersect(self, nums1, nums2):
        """
        :type nums1: List[int]
        :type nums2: List[int]
        :rtype: List[int]
        """
        nums1.sort()
        nums2.sort()
        index_1 = 0
        index_2 = 0
        inter = []

        while index_1 < len(nums1) and index_2 < len(nums2):
            if nums1[index_1] == nums2[index_2]:
                inter.append(nums1[index_1])
                index_1 += 1
                index_2 += 1
            elif nums1[index_1] < nums2[index_2]:
                index_1 += 1
            else:
                index_2 += 1

        return inter