Codeforces Round #563 (Div. 2) C. Ehab and a Special Coloring Problem
链接:https://codeforces.com/contest/1174/problem/C
题意:
You're given an integer nn. For every integer ii from 22 to nn, assign a positive integer aiai such that the following conditions hold:
- For any pair of integers (i,j)(i,j), if ii and jj are coprime, ai≠ajai≠aj.
- The maximal value of all aiai should be minimized (that is, as small as possible).
A pair of integers is called coprime if their greatest common divisor is 11.
思路:
筛法,把下标为素数的赋予新值,他的倍数再赋予同样的值即可。
代码:
#include <bits/stdc++.h> using namespace std; typedef long long LL;
const int MAXN = 3e5 + 10;
const int MOD = 1e9 + 7;
int n, m, k, t; int a[MAXN]; int main()
{
cin >> n;
int cnt = 0, pos = 0;
for (int i = 2;i <= n;i++)
{
if (a[i] != 0)
continue;
// cout << i << endl;
a[i] = ++pos;
cnt++;
int j = 2*i;
while (j <= n)
{
a[j] = pos;
j += i;
cnt++;
}
// if (cnt >= n-1)
// break;
}
for (int i = 2;i <= n;i++)
cout << a[i] << ' ' ;
cout << endl; return 0;
}
Codeforces Round #563 (Div. 2) C. Ehab and a Special Coloring Problem的更多相关文章
- Codeforces Round #563 (Div. 2) E. Ehab and the Expected GCD Problem
https://codeforces.com/contest/1174/problem/E dp 好题 *(if 满足条件) 满足条件 *1 不满足条件 *0 ///这代码虽然写着方便,但是常数有点大 ...
- Codeforces Round #525 (Div. 2)E. Ehab and a component choosing problem
E. Ehab and a component choosing problem 题目链接:https://codeforces.com/contest/1088/problem/E 题意: 给出一个 ...
- Codeforces Round #525 (Div. 2)D. Ehab and another another xor problem
D. Ehab and another another xor problem 题目链接:https://codeforces.com/contest/1088/problem/D Descripti ...
- Codeforces Round #563 (Div. 2) B. Ehab Is an Odd Person
链接:https://codeforces.com/contest/1174/problem/B 题意: You're given an array aa of length nn. You can ...
- Codeforces Round #563 (Div. 2) A. Ehab Fails to Be Thanos
链接:https://codeforces.com/contest/1174/problem/A 题意: You're given an array aa of length 2n2n. Is it ...
- Codeforces Round #563 (Div. 2) F. Ehab and the Big Finale
后续: 点分治标程 使用father数组 比使用vis数组优秀(不需要对vis初始化) https://codeforces.com/problemset/problem/1174/F https:/ ...
- Codeforces Round #525 (Div. 2) D. Ehab and another another xor problem(待完成)
参考资料: [1]:https://blog.csdn.net/weixin_43790474/article/details/84815383 [2]:http://www.cnblogs.com/ ...
- Codeforces Round #525 (Div. 2) E. Ehab and a component choosing problem 数学
题意:给出树 求最大的sigma(a)/k k是选取的联通快个数 联通快不相交 思路: 这题和1个序列求最大的连续a 的平均值 这里先要满足最大平均值 而首先要满足最大 也就是一个数的时候可 ...
- Codeforces Round #525 (Div. 2) D. Ehab and another another xor problem(交互题 异或)
题目 题意: 0≤a,b<2^30, 最多猜62次. 交互题,题目设定好a,b的值,要你去猜.要你通过输入 c d : 如果 a^c < b^d ,会反馈 -1 : 如果 a^c = b^ ...
随机推荐
- python读写txt大文件
直接上代码: import easygui import os path = easygui.fileopenbox()#path是打开的文件的全路径 if path:#如果选择打开文件,没有选择取消 ...
- 尚学堂xml学习笔记
1.打开eclipse,文件-新建java project,输入文件的名字,比如输入20181112. 2.对着src右键,选择new-file,输入文件名字,比如:book.xml. 3.开始写.x ...
- Android Studio 字体大小和背景色的设置
豆绿色的RGB值:#C7EDCC 1.打开Android Studio——>Ctrl+Alt+s 或者 File——>Settings 2.在弹窗中选中“Colors&Fonts” ...
- X-Forward-For ip
用 Firefox 的Moify Headers 插件 服务器重新配置X-Forward-For 为正确的值. 如对典型的nginx + php fastcgi 环境( nginx 与 php fas ...
- Linux网络编程之select、poll、epoll的比较,以及epoll的水平触发(LT)和边缘触发(ET)
Linux的网络通信先后推出了select.poll.epoll三种模式. select有以下三个问题: (1)每次调用select,都需要把fd集合从用户态拷贝到内核态,这个开销在fd很多时会很大. ...
- form 提交数据编码梳理
之前对form单提交的操作一直都是迷迷糊糊,知道怎么用,但是随着ajax2的出现,我们有更多的方式操作form表单提交,但是底层的原理我们要好好的做个梳理. 常见的form提交有post和get这两种 ...
- PS 滤镜— —球面化效果
clc; clear all; close all; addpath('E:\PhotoShop Algortihm\Image Processing\PS Algorithm'); I=imread ...
- 【Shell】变量的取用、删除、取代与替换
——来自<鸟哥的Linux私房菜> ——总结做方便查阅之用 变量的取用: echo echo $variableecho $PATHecho ${PATH} 变量的配置守则1.变量与变量内 ...
- Codeforces 762D Maximum path 动态规划
Codeforces 762D 题目大意: 给定一个\(3*n(n \leq 10^5)\)的矩形,从左上角出发到右下角,规定每个格子只能经过一遍.经过一个格子会获得格子中的权值.每个格子的权值\(a ...
- nagios客户端安装与配置windows篇
一.被监控的windows xp客户端的配置 1.安装NSClient++并安装下载地址: http://sourceforge.net/projects/nscplusNSClient++-0.3. ...