CodeForces 596C Wilbur and Points

先对n个点分类，然后按题意要求构造，构造的时候判断这个点的右上方之前是否有点，判断可以用线段树来操作。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<map>
#include<algorithm>
using namespace std;
const int maxn=+;
vector<int>g[*maxn],FX,FY;
int w[maxn];
struct X
{
    int x,y,id;
}s[maxn],tmp[maxn];
int n,Max;
int segtree[*maxn];
bool cmp(const X&a,const X&b)  {return a.x<b.x;}
void quary(int L,int R,int l,int r,int rt)
{
    if(L<=l&&r<=R) {Max=max(Max,segtree[rt]); return ;}
    int m=(l+r)/;
    if(L<=m) quary(L,R,l,m,*rt);
    if(R>m) quary(L,R,m+,r,*rt+);
}
void update(int pos,int val,int l,int r,int rt)
{
    if(l==r&&l==pos) { segtree[rt]=val; return; }
    int m=(l+r)/;
    if(pos<=m) update(pos,val,l,m,*rt);
    else update(pos,val,m+,r,*rt+);
    segtree[rt]=max(segtree[*rt],segtree[*rt+]);
}
int main()
{
    scanf("%d",&n); FX.clear(); FY.clear();
    for(int i=;i<=n;i++) scanf("%d%d",&s[i].x,&s[i].y);
    for(int i=;i<=n;i++) scanf("%d",&w[i]);
    sort(s+,s++n,cmp);
    for(int i=;i<=n;i++) g[s[i].y-s[i].x+].push_back(i);
    bool fail=; map<int,int>h; h.clear();
    memset(segtree,-,sizeof segtree);
    for(int i=;i<=n;i++)
    {
        if(h[w[i]]==g[w[i]+].size()) {fail=;break;}
        int id=g[w[i]+][h[w[i]]];
        Max=-; quary(s[id].x,,,,);
        if(Max>=s[id].y){fail=;break;}
        update(s[id].x,s[id].y,,,);
        int tmpx=s[id].x,tmpy=s[id].y;
        FX.push_back(tmpx); FY.push_back(tmpy);  h[w[i]]++;
    }
    if(fail==)
    {
        printf("YES\n");
        for(int i=;i<FX.size();i++) printf("%d %d\n",FX[i],FY[i]);
    }
    else printf("NO\n");
    return ;
}