在二维平面上计算出两个由直线构成的矩形叠加覆盖后的面积。

假设面积不会超出int的范围。

详见:https://leetcode.com/problems/rectangle-area/description/

Java实现:

class Solution {
public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
int sum = (C - A) * (D - B) + (H - F) * (G - E);
if (E >= C || F >= D || B >= H || A >= G){
return sum;
}
return sum - ((Math.min(G, C) - Math.max(A, E)) * (Math.min(D, H) - Math.max(B, F)));
}
}

C++实现:

class Solution {
public:
int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
int sum = (C - A) * (D - B) + (H - F) * (G - E);
if (E >= C || F >= D || B >= H || A >= G)
{
return sum;
}
return sum - ((min(G, C) - max(A, E)) * (min(D, H) - max(B, F)));
}
};

  参考:https://www.cnblogs.com/grandyang/p/4563153.html

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