XMU C语言程序设计实践（2）

任务一：颠倒的世界

小明最近突然喜欢倒着写字，写出来的句子全是颠倒的，也就是把一句话里的字符全都逆序写，譬如“I Love This Game！”，他就偏偏要写成“!emaG sihT evoL I”弄的小华同他Email交流都很难受。请你帮助小华解决这个问题，将输入的字符串全都还原成本来的面目。

任务1要求：

利用main函数带参数的功能，编写程序，将命令行中的字符串全部逆序显示出来。例如编写的可执行文件为go.exe 那么运行 go !emaG sihT evoL I 时，显示出I Love This Game！

任务二：时间转换

由于工作原因，小明常常需要签署文件日期，但他比较偷懒，都用阿拉伯数字签署，譬如3.8表示三月八日，7.12表示七月十二日。最近公司改组成外资企业，主管要求将所有的日期全部更改为英文表示，一来同国际接轨，二来也不容易篡改，譬如将3.8表示为March the eighth 面对这么多的日期，小明犯愁了，他英文不好，那么多的英文单词他记不住。而且小明还是个马大哈，有时候居然会签出3.32（三月三十二日）这样的日期，为了避免被上司责备，趁着这次机会也赶快一并修改。请你帮助小明完成这个任务。

任务2要求：

利用main函数带参数的功能，编写程序，将命令行中的字符串翻译成英文表示，每行显示一个日期，同时需检查日期表示是否有误，如有误，请给出提示。例如：编写的可执行文件为go.exe 那么运行go 
3.8  5.5  4.38 时显示

March the eighth

May the fifth

Error

任务三：时间转换(续)

小明觉得这么一点点的手工输入还是有点麻烦，他把需要翻译的日期都整理到文本文件in.txt中，请你帮助小明，将其中的内容翻译完毕后保存到文本文件out.txt中，便于他统一处理。

任务3要求：翻译过程同任务2，将结果保存至文件out.txt中

第一题：

 #include<stdio.h>
 #include<stdlib.h>
 #include<string.h>
 #define max(a,b) ((a)>(b)?(a):(b))
 #define min(a,b) ((a)<(b)?(a):(b))
 #define abs(a) ((a)>0?(a):(-(a)))
 #define sqr(a) ((a)*(a))
 #define swap(a,b) (a)^=(b),(b)^=(a),(a)^=(b)
 #define eps 1e-8
 #define MAX 0x7f7f7f7f
 #define N 104
 int a[N];
 int main(int argc,char* argv[])
 {
     int i,j,k;
     for(i=argc-;i>;i--)
     {
         for(j=strlen(argv[i])-;j>=;j--)
             putchar(argv[i][j]);
         printf(" ");
     }
     puts("");
     return ;
 }
 /*
 Q:\xxx\111\222\bin\Debug\222 !emaG sihT evoL I
 */

第二题：

 #include<stdio.h>
 #include<stdlib.h>
 #include<string.h>
 #define max(a,b) ((a)>(b)?(a):(b))
 #define min(a,b) ((a)<(b)?(a):(b))
 #define abs(a) ((a)>0?(a):(-(a)))
 #define sqr(a) ((a)*(a))
 #define swap(a,b) (a)^=(b),(b)^=(a),(a)^=(b)
 #define eps 1e-8
 #define MAX 0x7f7f7f7f
 #define N 104
 int m,d;
 int mon[]={,,,,,,,,,,,,};
 char *M[]={"","January","February","March","April","May","June","July","August","September","October","November","December"};
 char *D[]={"","first","second","third","fourth","fifth","sixth","seventh","eighth","ninth","tenth","eleventh","twelfth","thirteenth","fourteenth","fifteenth","sixteenth","seventeenth","eighteenth","nineteenth","twentieth","twenty-first","twenty-second","twenty-third","twenty-fourth","twenty-fifth","twenty-sixth","twenty-seventh","twenty-eighth","twenty-ninth","thirtieth","thirty-first"};
 void work(char s[])
 {
     int i;
     m=d=;
     if(s[]=='.')
     {
         m=(s[]-'')*+s[]-'';
         i=;
     }
     else if(s[]=='.')
     {
         m=s[]-'';
         i=;
     }
     for(;i<strlen(s);i++)
         d=d*+s[i]-'';
 }
 int main(int argc,char * argv[])
 {
     int i,j,k;
     for(i=;i<argc;i++)
     {
         work(argv[i]);
         if(d>mon[m] || d< || m> ||m<)puts("Error");
         else printf("%s the %s",*(M+m),*(D+d));
         puts("");
     }
     return ;
 }
 /*
 Q:\xxx\111\222\bin\Debug\222 3.8 5.5 4.38
 */

第三题：

 #include<stdio.h>
 #include<stdlib.h>
 #include<string.h>
 #define max(a,b) ((a)>(b)?(a):(b))
 #define min(a,b) ((a)<(b)?(a):(b))
 #define abs(a) ((a)>0?(a):(-(a)))
 #define sqr(a) ((a)*(a))
 #define swap(a,b) (a)^=(b),(b)^=(a),(a)^=(b)
 #define eps 1e-8
 #define MAX 0x7f7f7f7f
 #define N 1004
 int m,d;
 int mon[]={,,,,,,,,,,,,};
 char argv[N];
 char *M[]={"","January","February","March","April","May","June","July","August","September","October","November","December"};
 char *D[]={"","first","second","third","fourth","fifth","sixth","seventh","eighth","ninth","tenth","eleventh","twelfth","thirteenth","fourteenth","fifteenth","sixteenth","seventeenth","eighteenth","nineteenth","twentieth","twenty-first","twenty-second","twenty-third","twenty-fourth","twenty-fifth","twenty-sixth","twenty-seventh","twenty-eighth","twenty-ninth","thirtieth","thirty-first"};
 void work(char s[])
 {
     int i;
     m=d=;
     if(s[]=='.')
     {
         m=(s[]-'')*+s[]-'';
         i=;
     }
     else if(s[]=='.')
     {
         m=s[]-'';
         i=;
     }
     for(;i<strlen(s);i++)
         d=d*+s[i]-'';
 }
 int main()
 {
     FILE *fp1=fopen("Q:\\xxx\\111\\111\\in.txt","r"),*fp=fopen("Q:\\xxx\\111\\111\\out.txt","w");
     int i,j,k;
     while(~fscanf(fp1,"%s",argv))
     {
         work(argv);
         if(d>mon[m] || d< || m> ||m<)fputs("Error\n",fp);
         else fprintf(fp,"%s the %s\n",*(M+m),*(D+d));
     }
     fclose(fp1);
     fclose(fp);
     return ;
 }
 /*
 Q:\xxx\111\111\bin\Debug\111 3.8 5.5 4.38 13.1 1.32 1.0 2.29 115123 3.31
 */