【数组】Unique Paths II
题目:
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
The total number of unique paths is 2.
Note: m and n will be at most 100.
思路:
这道题跟Unique Paths的区别在于路线中有了障碍物,只需把障碍物处路线数变为0即可。
/**
* @param {number[][]} obstacleGrid
* @return {number}
*/
var uniquePathsWithObstacles = function(obstacleGrid) {
var f=[];
var m=obstacleGrid.length,n=obstacleGrid[0].length;
for(var i=0;i<m;i++){
f[i]=[];
} for(var i=0;i<m;i++){
if(obstacleGrid[i][0]==1){
f[i][0]=0;
for(var j=i+1;j<m;j++){
f[j][0]=0;
}
break
}else{
f[i][0]=1;
}
} for(var i=0;i<n;i++){
if(obstacleGrid[0][i]==1){
f[0][i]=0;
for(var j=i+1;j<n;j++){
f[0][j]=0;
}
break;
}else{
f[0][i]=1
}
} for(var i=1;i<m;i++){
for(var j=1;j<n;j++){
if(obstacleGrid[i][j]==1){
f[i][j]=0;
}else{
f[i][j]=f[i-1][j]+f[i][j-1];
}
}
} return f[m-1][n-1]; };
【数组】Unique Paths II的更多相关文章
- 62. Unique Paths && 63 Unique Paths II
https://leetcode.com/problems/unique-paths/ 这道题,不利用动态规划基本上规模变大会运行超时,下面自己写得这段代码,直接暴力破解,只能应付小规模的情形,当23 ...
- 【Leetcode】【Medium】Unique Paths II
Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How m ...
- 动态规划小结 - 二维动态规划 - 时间复杂度 O(n*n)的棋盘型,题 [LeetCode] Minimum Path Sum,Unique Paths II,Edit Distance
引言 二维动态规划中最常见的是棋盘型二维动态规划. 即 func(i, j) 往往只和 func(i-1, j-1), func(i-1, j) 以及 func(i, j-1) 有关 这种情况下,时间 ...
- LEETCODE —— Unique Paths II [动态规划 Dynamic Programming]
唯一路径问题II Unique Paths II Follow up for "Unique Paths": Now consider if some obstacles are ...
- 【leetcode】Unique Paths II
Unique Paths II Total Accepted: 22828 Total Submissions: 81414My Submissions Follow up for "Uni ...
- 61. Unique Paths && Unique Paths II
Unique Paths A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagra ...
- LeetCode: Unique Paths II 解题报告
Unique Paths II Total Accepted: 31019 Total Submissions: 110866My Submissions Question Solution Fol ...
- 【LeetCode练习题】Unique Paths II
Unique Paths II Follow up for "Unique Paths": Now consider if some obstacles are added to ...
- LeetCode之“动态规划”:Minimum Path Sum && Unique Paths && Unique Paths II
之所以将这三道题放在一起,是因为这三道题非常类似. 1. Minimum Path Sum 题目链接 题目要求: Given a m x n grid filled with non-negative ...
- [LeetCode] Unique Paths && Unique Paths II && Minimum Path Sum (动态规划之 Matrix DP )
Unique Paths https://oj.leetcode.com/problems/unique-paths/ A robot is located at the top-left corne ...
随机推荐
- Linux命令行下的vim文本编辑器
Linux命令行下的vim文本编辑器 下面这个网站的地址讲解的非成分清楚!!!! http://blog.csdn.net/niushuai666/article/details/7275406 学习 ...
- mybatis如何直接 执行传入的任意sql语句 并按照顺序取出查询的结果集
需求: 1.直接执行前端传来的任何sql语句,parameterType="String", 2.对于任何sql语句,其返回值类型无法用resultMap在xml文件里配置或者返回 ...
- HighCharts使用总结
1.常用属性 chart: type:areaspline(线面图).arearange(区间图) zoomType: 缩放类型(沿着'xy'轴缩放) alignTicks:设置坐标轴刻度对齐. 当有 ...
- 配置ssh使用socks代理
ssh -o ProxyCommand='nc -x 127.0.0.1:1080 %h %p' username@server
- mysql设定或修改密码的三个方法
为用户设定密码: 1.mysql>SET PASSWORD FOR 'USERNAME'@'HOST'=PASSWORD('password'); 2.# mysqladmin -uUSERNA ...
- poj 2981 Strange Way to Express Integers (中国剩余定理不互质)
http://poj.org/problem?id=2891 Strange Way to Express Integers Time Limit: 1000MS Memory Limit: 13 ...
- Dapper.Contrib.Extensions问题
Dapper.Contrib.Extensions问题 Dapper.Extension.1.0.0.1\lib\net45\Dapper.Extension.dll Dapper.Contrib.1 ...
- 决定以后再做公司的项目的时候,能够用其他语言的绝对不用delphi
1.delphi7的IDE真的很不友好 2.delphi7的控件有的有问题 3.delphi7居然不支持结构体的泛型存储 4.网上的解决文档超少,一些小bug,就要折腾半天 5.pascal语法太过结 ...
- iterrows() 函数对dataframe进行遍历
for循环遍历dataframe,返回有一个元祖类型,第一个是行的索引,第二个是series,是每一行的内容.
- CTF 介绍及杂项
CTF(Capture The Flag)中文一般译作夺旗赛,在网络安全领域中指的是网络安全技术人员之间进行技术竞技的一种比赛形式.CTF起源于1996年DEFCON全球黑客大会,以代替之前黑客们通过 ...