A. Vanya and Cubes
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Vanya got n cubes. He decided to build a pyramid from them. Vanya wants to build the pyramid as follows: the top level of the pyramid must consist of 1 cube, the second level must consist of 1 + 2 = 3 cubes, the third level must have 1 + 2 + 3 = 6 cubes, and so on. Thus, the i-th level of the pyramid must have 1 + 2 + ... + (i - 1) + i cubes.

Vanya wants to know what is the maximum height of the pyramid that he can make using the given cubes.

Input

The first line contains integer n (1 ≤ n ≤ 104) — the number of cubes given to Vanya.

Output

Print the maximum possible height of the pyramid in the single line.

Sample test(s)
Input
1
Output
1
Input
25
Output
4
Note

Illustration to the second sample:

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
int main()
{
int n;
cin>>n;
int ans=;
int kill=;
int sum=;
while(ans<=n)
{
sum+=kill;
ans+=sum;
kill++;
}
cout<<kill-<<endl;
return ;
}

Codeforces Round #280 (Div. 2) A. Vanya and Cubes 水题的更多相关文章

  1. Codeforces Round #355 (Div. 2) A. Vanya and Fence 水题

    A. Vanya and Fence 题目连接: http://www.codeforces.com/contest/677/problem/A Description Vanya and his f ...

  2. Codeforces Round #280 (Div. 2)E Vanya and Field(简单题)

    转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud 本场题目都比较简单,故只写了E题. E. Vanya and Field Vany ...

  3. Codeforces Round #280 (Div. 2) E. Vanya and Field 思维题

    E. Vanya and Field time limit per test 2 seconds memory limit per test 256 megabytes input standard ...

  4. Codeforces Round #308 (Div. 2) D. Vanya and Triangles 水题

    D. Vanya and Triangles Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/55 ...

  5. Codeforces Round #355 (Div. 2) C. Vanya and Label 水题

    C. Vanya and Label 题目连接: http://www.codeforces.com/contest/677/problem/C Description While walking d ...

  6. Codeforces Round #297 (Div. 2)A. Vitaliy and Pie 水题

    Codeforces Round #297 (Div. 2)A. Vitaliy and Pie Time Limit: 2 Sec  Memory Limit: 256 MBSubmit: xxx  ...

  7. Codeforces Round #280 (Div. 2) A B C 暴力 水 贪心

    A. Vanya and Cubes time limit per test 1 second memory limit per test 256 megabytes input standard i ...

  8. Codeforces Round #290 (Div. 2) A. Fox And Snake 水题

    A. Fox And Snake 题目连接: http://codeforces.com/contest/510/problem/A Description Fox Ciel starts to le ...

  9. Codeforces Round #322 (Div. 2) A. Vasya the Hipster 水题

    A. Vasya the Hipster Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/581/p ...

随机推荐

  1. 一个不错的linux学习资料下载的网址

    本文比较完整的讲述GNU make工具,涵盖GNU make的用法.语法.同时重点讨论如何为一个工程编写Makefile.作为一个Linux程序员,make工具的使用以及编写Makefile是必需的. ...

  2. sublime Text快捷键(超级全)

    sublime Text快捷键(超级全) Ctrl+Shift+P:打开命令面板 Ctrl+P:搜索项目中的文件 Ctrl+G:跳转到第几行 Ctrl+W:关闭当前打开文件 Ctrl+Shift+W: ...

  3. 用js面向对象思想封装插件

    js是基于原型的面向对象语言,如果你学过java,c#等正统面向对象语言,你会难以理解js的面向对象,他和普通的面向对象不太一样,今天,我们通过封装一个toast插件,来看看js面向对象是如何运行的. ...

  4. linux java配置

    1.java配置 配置环境变量在/etc/profile下增加# set Java environmentJAVA_HOME=/usr/share/jdk1.6.0_43PATH=$JAVA_HOME ...

  5. Python爬虫之HDU提交数据

    前一篇http://www.cnblogs.com/liyinggang/p/6094338.html 使用了爬虫爬取hdu 的代码,今天实现了将数据向hdu 提交的功能,接下来就是需要将两个功能合并 ...

  6. 使用apt install和使用apt-get install的区别是什么

    apt-get是老版的命令,apt是新版的命令,apt还包含了apt-get cache等等,用起来更方便.因为apt刚刚出来,所以允许有apt-get和apt共存,以后apt-get就要淘汰了.

  7. entityframework导航属性筛选

    ); //会在sql代码中生成Street = "上海"代码 var address1 = db.Entry(user).Collection(b => b.Address) ...

  8. IIS部署asp.net MVC 出现错误 403.14-Forbidden解决办法

    可能性一: <system.webServer>   <validationvalidateIntegratedModeConfiguration="false" ...

  9. linux 101 hacks 4stat diff ac

    stat 命令 stat 命令那个可以用来查看文件或者文件系统的状态和属性.显示一个文件或目录的属性 $ stat /etc/my.cnf File: `/etc/my.cnf' Size: Bloc ...

  10. 【POJ】1740.A New Stone Game

    题解 想去学习一下博弈论的SG函数 不过貌似这道题就是猜结论并且证明 题意是,随便选择一堆石子,扔掉至少一个,然后从扔石子的这堆里选择任意多(可以不选)放到其他任意多的未选择完的石堆里 一堆石子,先手 ...