Given two binary strings, return their sum (also a binary string).

For example,

a = "11"

b = "1"

Return "100".

求数字字符串的二进制和。

同之前的数组代表数字,两个数组相加一样。仅仅只是进位变成了2.可能两个串的长度不一样,故逆转。从左到右加下去。最后再逆转。

	public static String addBinary(String a, String b) {
StringBuilder ar = new StringBuilder(a).reverse();
StringBuilder br = new StringBuilder(b).reverse();
StringBuilder result = new StringBuilder();
int len = Math.max(a.length(), b.length());
int carry = 0;//进位
for (int i = 0; i < len; i++) {
int t1 = (i >= a.length() ? 0 : (ar.charAt(i) - '0'));
int t2 = (i >= b.length() ? 0 : (br.charAt(i) - '0'));
int t3 = t1 + t2 + carry;
carry = t3 / 2;
t3 = t3 % 2;
result.append(t3);
}
if (carry != 0)
result.append(carry);
result.reverse();
return result.toString();
}

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