UVa 124 - Following Orders
题目大意:给一个变量列表和变量的大小关系,输出所有的满足约束的序列。
构建为有向图,然后就是拓扑排序,使用回溯输出所有的结果。
#include <cstdio>
#include <cstring>
#include <cctype>
#include <map>
#include <algorithm>
#include <vector>
using namespace std;
#define N 26 map<char, int> id;
map<int, char> var;
vector<int> AdjList[N], ans;
int n, indegree[]; void newNode(char c)
{
if (!id.count(c))
{
int t = id.size();
id[c] = t;
var[t] = c;
}
} void dfs(int cur)
{
if (cur == n)
{
for (int i = ; i < n; i++) printf("%c", var[ans[i]]);
printf("\n");
return;
}
for (int i = ; i < n; i++)
if (indegree[i] == )
{
indegree[i] = -;
ans.push_back(i);
vector<int> vt;
for (int j = ; j < AdjList[i].size(); j++)
{
int v = AdjList[i][j];
vt.push_back(v);
indegree[v]--;
}
dfs(cur+);
for (int j = ; j < vt.size(); j++)
indegree[vt[j]]++;
ans.pop_back();
indegree[i] = ;
}
} int main()
{
#ifdef LOCAL
freopen("in", "r", stdin);
freopen("out", "w", stdout);
#endif
char str[];
bool first = true;
while (gets(str))
{
int len = strlen(str);
id.clear();
var.clear();
vector<char> varList;
for (int i = ; i < len; i++)
if (islower(str[i]))
varList.push_back(str[i]);
sort(varList.begin(), varList.end());
for (int i = ; i < varList.size(); i++) newNode(varList[i]);
n = id.size();
gets(str);
len = strlen(str);
vector<int> rel;
for (int i = ; i < len; i++)
if (islower(str[i]))
rel.push_back(id[str[i]]);
for (int i = ; i < N; i++) indegree[i] = ;
for (int i = ; i < N; i++) AdjList[i].clear();
for (int i = ; i+ < rel.size(); i += )
{
AdjList[rel[i]].push_back(rel[i+]);
indegree[rel[i+]]++;
}
if (first) first = false;
else printf("\n");
dfs();
}
return ;
}
第一次忘了给变量列表排序,结果WA了一次...
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