88. Merge Sorted Array(从后向前复制)
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
nums1已经是m+n长度了,不用新申请空间。
从后向前复制。
class Solution:
def merge(self, l1, m, l2, n):
"""
:type nums1: List[int]
:type m: int
:type nums2: List[int]
:type n: int
:rtype: void Do not return anything, modify nums1 in-place instead.
"""
i = m - 1
j = n - 1 end = m+n-1
while(i >= 0 and j >= 0):
if(l1[i] > l2[j]):
l1[end] = l1[i]
i-=1
else:
l1[end] = l2[j]
j -= 1
end -=1 while (j>=0):
l1[end] = l2[j]
j -= 1
end-=1
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