HDU-1002.大数相加(字符串模拟)

　　本题大意：给出两个1000位以内的大数a 和b，让你计算a + b的值。

　　本题思路：字符串模拟就能过，会Java的大佬应该不会点进来......

　　参考代码：

 #include <cstdio>
 #include <cstring>
 using namespace std;

 const int maxn =  + ;
 int  t, Case = , now;
 int ans[maxn];
 char s1[maxn], s2[maxn];

 int main () {
     scanf("%d", &t);
     while(t --) {
         if(Case > ) printf("\n");
         now = ;
         memset(ans, , sizeof(ans));
         scanf("%s %s", s1, s2);
         int len1 = strlen(s1), len2 = strlen(s2), i = len1 - , j = len2 - ;
         while(i >=  && j >= ) {
             ans[now + ] =  (ans[now] + s1[i] + s2[j] -  * '') / ;
             ans[now] = (ans[now ++] + s1[i --] + s2[j --] -  * '') % ;
         }
         while(i >= ) {
             ans[now + ] = (ans[now] + s1[i] - '') / ;
             ans[now] = (ans[now ++] + s1[i --] - '') % ;
         }
         while(j >= ) {
             ans[now + ] = (ans[now] + s2[j] - '') / ;
             ans[now] = (ans[now ++] + s2[j --] - '') % ;
         }
         printf("Case %d:\n%s + %s = ", ++ Case, s1, s2);
         if(ans[now] > )    now ++;
         for(i = now - ; i >= ; i --)
             printf("%d", ans[i]);
         printf("\n");
     }
     return ;
 }