DataTable 转 JSON,XML转JSON

今天总结一下关于DataTable,XML转JSON的方法：

首先需要引入命名空间： using Newtonsoft.Json 1 public string DataTableToJsonWithStringBuilder(DataTable table)

     {
         var jsonString = new StringBuilder();
         if (table.Rows.Count > )
         {
               jsonString.Append("[");
             for (int i = ; i < table.Rows.Count; i++)
             {
                 jsonString.Append("{");
                 for (int j = ; j < table.Columns.Count; j++)
                 {
                     if (j < table.Columns.Count - )
                     {
                         jsonString.Append("\"" + table.Columns[j].ColumnName.ToString()
                      + "\":" + "\""
                      + table.Rows[i][j].ToString() + "\",");
                     }
                     else if (j == table.Columns.Count - )
                     {
                         jsonString.Append("\"" + table.Columns[j].ColumnName.ToString()
                      + "\":" + "\""
                      + table.Rows[i][j].ToString() + "\"");
                     }
                 }
                 if (i == table.Rows.Count - )
                 {
                     jsonString.Append("}");
                 }
                 else
                 {
                     jsonString.Append("},");
                 }
             }
               jsonString.Append("]");
         }
         return jsonString.ToString();
     }

调用：

var xmlToJson = DataTableToJsonWithStringBuilder(newdt);// datatable转json数组

//XML转JSON

var xmlToJson1 = JsonConvert.SerializeXmlNode(child, Newtonsoft.Json.Formatting.None, true);