ExceptionHandler 异常公共处理

异常的公共处理很多种，采用注解的方式，拦截器的方式等都可以，我采用的是继承 AbstractHandlerExceptionResolver 来实现，

上代码

package com.yun.util;

import java.io.IOException;
import java.sql.SQLException;
import java.util.HashMap;
import java.util.Map;
import java.util.concurrent.TimeoutException;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.web.method.HandlerMethod;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.handler.AbstractHandlerExceptionResolver;

import com.alibaba.druid.support.json.JSONUtils;

public class ExceptionHandler extends AbstractHandlerExceptionResolver {

    private static final Logger LOGGER = LoggerFactory.getLogger(ExceptionHandler.class);

    @Override
    protected ModelAndView doResolveException(HttpServletRequest request,
            HttpServletResponse response, Object handler, Exception ex) {

        // SQLException 数据库异常
        if (ex instanceof SQLException) {
            SQLException e = (SQLException) ex;
            LOGGER.error("数据库异常:{}",e.getMessage());
        }
        // RuntimeException>NullPointerException,IllegalArgumentException...
        if (ex instanceof RuntimeException) {
            RuntimeException e = (RuntimeException) ex;
            LOGGER.error("运行时异常:{}",e.getMessage());
        }

        // IOException
        if (ex instanceof IOException) {
            IOException e = (IOException) ex;
            LOGGER.error("IO异常:{}",e.getMessage());
        }

        // TimeoutException
        if (ex instanceof TimeoutException) {
            TimeoutException e = (TimeoutException) ex;
            LOGGER.error("超时:{}",e.getMessage());
        }

        if(handler instanceof HandlerMethod){

            HandlerMethod handlerMethod = (HandlerMethod) handler;
            Class returnType = handlerMethod.getMethod().getReturnType();
            try {
                if(returnType == String.class||returnType==void.class){
                    String rsp = JSONUtils.toJSONString(ex);
                    response.setContentType("application/json;charset=UTF-8");
                    response.setCharacterEncoding("UTF-8");
                    response.getWriter().write(rsp);
                    new ModelAndView();
                }
                if(returnType == ModelAndView.class){
                    Map<String, Object> model = new HashMap<String, Object>();
                    model.put("ex", ex);
                    return new ModelAndView("error/error", model);
                }
            } catch (Exception e) {
                LOGGER.error("异常:{}", e.getMessage());
            }

        }

        return new ModelAndView();

    }

}

接下来只需要注册到spring中就ok了。

<!-- 异常处理 -->
    <bean class="com.midea.jr.efc.eac.core.web.ExceptionHandler"></bean>

二： 另一种方式  注解 ControllerAdvice

package com.yun.util;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.beans.TypeMismatchException;
import org.springframework.web.HttpRequestMethodNotSupportedException;
import org.springframework.web.bind.MissingServletRequestParameterException;
import org.springframework.web.bind.annotation.ControllerAdvice;
import org.springframework.web.bind.annotation.ExceptionHandler;
import org.springframework.web.bind.annotation.ResponseBody;

@ControllerAdvice
public class CommonExceptiomHandler {

    private Logger logger =  LoggerFactory.getLogger(this.getClass());

    @ExceptionHandler(IllegalArgumentException.class)
    @ResponseBody
    public String illegalArgumentException(IllegalArgumentException e) {
        logger.error(e.getMessage());
        return new String("param error");
    }

    @ExceptionHandler(MissingServletRequestParameterException.class)
    @ResponseBody
    public String MissingServletRequestParameterException(MissingServletRequestParameterException e) {
        logger.error(e.getMessage());
        return new String("missing servlet request");
    }

    @ExceptionHandler(TypeMismatchException.class)
    @ResponseBody
    public String typeMismatchException(TypeMismatchException e) {
        logger.error(e.getMessage());
        return new String("type mismatch error");
    }

    @ExceptionHandler(HttpRequestMethodNotSupportedException.class)
    @ResponseBody
    public String httpRequestMethodNotSupportedException(Exception e) {
        logger.error(e.getMessage());
        return new String("http request method not supported");
    }

    @ExceptionHandler(Exception.class)
    @ResponseBody
    public String defaultException(Exception e) {
        logger.error(e.getMessage());
        return new String("system error");
    }

}