Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.(Easy)

分析:

利用辅助函数求深度,然后根据heighted-balanced定义判定即可

代码:

 class Solution {
int depth(TreeNode* root) {
if (root == nullptr) {
return ;
}
return max(depth(root -> left), depth(root -> right)) + ;
}
public:
bool isBalanced(TreeNode* root) {
if (root == nullptr) {
return true;
}
int left = depth(root -> left);
int right = depth(root -> right);
if (abs(left - right) <= && isBalanced(root -> left) && isBalanced(root -> right)) {
return true;
}
return false;
}
};

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