#include<bits/stdc++.h>
using namespace std;
#define INF 0x3f3f3f3f
int dis[];
int visit[];
int SSSP[][];
void dijkstra(int x,int n)
{
int pos;
int minn;
for(int i=;i<=n;i++)
{
dis[i]=SSSP[][i];
}
visit[x]=;
dis[x]=;
for(int i=;i<=n;i++)
{
minn=INF;
pos=;
for(int j=;j<=n;j++)
{
if(!visit[j]&&dis[j]<minn)
{
pos=j;
minn=dis[j];
} }
if(pos==) break;
else
{
visit[pos]=;
for(int j=;j<=n;j++)
{
if(!visit[j]&& dis[pos]+SSSP[pos][j]<dis[j])
dis[j]=dis[pos]+SSSP[pos][j];
}
} }
}
int main()
{
while()
{
int n,m; cin>>n>>m;
if(n==&&m==) break; int zzzzz=; memset(visit,,sizeof(visit));
memset(dis,,sizeof(dis));
memset(SSSP,,sizeof(SSSP)); for(int i=;i<=n;i++)
{
for(int j=;j<=n;j++)
SSSP[i][j]=INF;
}
int a[];
int b[];
int t[];
for(int i=;i<=m;i++)
{
cin>>a[i]>>b[i]>>t[i];
SSSP[a[i]][b[i]]=t[i];
SSSP[b[i]][a[i]]=t[i];
}
dijkstra(,n); //cout<<"*****"<<dis[n]<<"*******"<<zzzzz<<"******"<<endl;
if(dis[n]==INF)
{
zzzzz=;
}
int maxn=dis[n]; for(int i=;i<n;i++)
{
// qu dian chong ding yi
if(zzzzz==) break;
for(int j=;j<=n;j++)
{
for(int j1=;j1<=n;j1++)
SSSP[j][j1]=INF;
}
for(int j=;j<=m;j++)
{
SSSP[a[j]][b[j]]=t[j];
SSSP[b[j]][a[j]]=t[j];
if(a[j]==i||b[j]==i)
{
SSSP[a[j]][b[j]]=INF;
SSSP[b[j]][a[j]]=INF;
}
}
// chong ding yi visit[] dis memset(visit,,sizeof(visit));
memset(dis,,sizeof(dis)); dijkstra(,n); // cout<<"*****"<<dis[n]<<"*******"<<zzzzz<<"******"<<endl;
if(dis[n]==INF)
{
zzzzz=;
}
if(dis[n]>maxn) maxn=dis[n];
}
if(zzzzz==)
cout<<maxn<<endl;
if(zzzzz==)
cout<<"Inf"<<endl;
}
}

hdu5173 How Many Maos Does the Guanxi Worth的更多相关文章

  1. hdu 5137 How Many Maos Does the Guanxi Worth 最短路 spfa

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  2. HDU 5137 How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 512000/5120 ...

  3. hdoj 5137 How Many Maos Does the Guanxi Worth【最短路枚举+删边】

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  4. HDU5137 How Many Maos Does the Guanxi Worth(枚举+dijkstra)

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  5. How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  6. HDU 5137 How Many Maos Does the Guanxi Worth 最短路 dijkstra

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  7. (hdoj 5137 floyd)How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  8. 杭电5137How Many Maos Does the Guanxi Worth

    How Many Maos Does the Guanxi Worth Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/5 ...

  9. ACM学习历程——HDU5137 How Many Maos Does the Guanxi Worth(14广州10题)(单源最短路)

    Problem Description    "Guanxi" is a very important word in Chinese. It kind of means &quo ...

随机推荐

  1. 遍历所有子物体中renderer(渲染器)中的material(材质)并改变其alpha值实现若隐若现的效果

    using UnityEngine;using System.Collections;using UnityEngine.UI; public class CubeControl : MonoBeha ...

  2. RabbitMQ 循环调度

    循环调度是针对Consumer消费者来说的.如果有多个Consumer订阅同一个队列的消息,RabbitMQ会自动按照顺序将消息发送到每一个Consumer手中. 就是这么简单!

  3. xml文档的读取

    #! /usr/bin/env python3 # -*- coding:utf-8 -*- import xml.dom.minidom  #该模块被用来处理xml文件 #打开xml文档 dom=x ...

  4. opencv3.0+vs2013安装记录

    为了能够更好的学习图像,我觉得opencv是一个必不可少的库,因此在以后的研究上使用opencv作为研究工具,与大家共同进步. 话归正题:先搭建opencv的环境. 1.下载安装包3.0 a,官网打开 ...

  5. SQL-1 选取表中某一属性最大值的所有信息 查找最晚入职员工的所有信息

    题目描述 查找最晚入职员工的所有信息CREATE TABLE `employees` (`emp_no` int(11) NOT NULL,`birth_date` date NOT NULL,`fi ...

  6. elk之elasticsearch安装

    环境: centos7 jdk8 参考: https://www.elastic.co/guide/en/elasticsearch/reference/current/rpm.htmlhttp:// ...

  7. tf 模型保存

    tf用 tf.train.Saver类来实现神经网络模型的保存和读取.无论保存还是读取,都首先要创建saver对象. 用saver对象的save方法保存模型 保存的是所有变量 save( sess, ...

  8. Java语法基础学习DaySix

    一.JavaBean——可重用组件 1.JavaBean是指符合以下标准的Java类: (1)类是公共的 (2)有一个无参的公共的构造器 (3)有属性,且有对应的get.set方法 2.好处 用户可以 ...

  9. synchronized(四)

    package com.bjsxt.base.sync005;/** * synchronized的重入 * @author alienware * */public class SyncDubbo1 ...

  10. 解决You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (order_name, customer)

    在学习hibernate一对多映射关系时,根据视频学习的时候,例子是顾客和订单的问题,一个顾客有多个订单.按照视频中的敲代码出现了You have an error in your SQL synta ...