Objhdu2001java

计算两点间的距离

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 168512    Accepted Submission(s):
59478

Problem Description

输入两点坐标（X1,Y1）,（X2,Y2）,计算并输出两点间的距离。

 

Input

输入数据有多组，每组占一行，由4个实数组成，分别表示x1,y1,x2,y2,数据之间用空格隔开。

 

Output

对于每组输入数据，输出一行，结果保留两位小数。

 

Sample Input

0 0 0 1

0 1 1 0

 

Sample Output

1.00

1.41

import java.util.*;
class Mian{
public static void main(String args[])
{Scanner cin=new Scanner(System.in);
while(cin.hasNext())
{ double x1=cin.nextDouble();
double y1=cin.nextDouble();
double x2=cin.nextDouble();
double y2=cin.nextDouble();
Point p1=new Point(x1,y1);
Point p2=new Point(x2,y2);
double dis=p2.distance(p1);
System.out.printf("%.2f",dis);
System.out.println();
}
}
}
class Point{
private double x;
private double y;
public Point(double x,double y)
{ this.x=x;
this.y=y;
}
public double distance(Point p)
{double dis=Math.sqrt((this.x-p.x)*(this.x-p.x)+(this.y-p.y)*(this.y-p.y));
return dis;
}
}