Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it 
will 
return 
false. 



Each 
letter
 in
 the
 magazine 
string 
can
 only 
be
 used 
once
 in
 your 
ransom
 note.

Note:
You may assume that both strings contain only lowercase letters.

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true
 class Solution {
public:
bool canConstruct(string ransomNote, string magazine) {
map<char,int> mpr,mpm;
map<char,int>::iterator itr,itm;
int i ,j;
for(i=; i < ransomNote.length();++i)
{
mpr[ransomNote[i]]++;
}
for(j = ; j<magazine.length();++j)
{
mpm[magazine[j]]++;
}
if(mpr.size() > mpm.size()) return false;
itr = mpr.begin();itm = mpm.begin();
while(itr != mpr.end() && itm != mpm.end())
{
char tmp = itr->first;
map<char,int>::iterator t; if(mpm.find(tmp) == mpm.end())
return false; if((int)(itr->second) > (int)(mpm.find(tmp)->second))
return false;
else
itr++;
}
return true; }
};

leetcode 383. Ransom Note的更多相关文章

  1. 14. leetcode 383. Ransom Note

    Given an arbitrary ransom note string and another string containing letters from all the magazines, ...

  2. Java [Leetcode 383]Ransom Note

    题目描述: Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 al ...

  3. LeetCode: 383 Ransom Note(easy)

    题目: Given an arbitrary ransom note string and another string containing letters from all the magazin ...

  4. 383. Ransom Note【easy】

    383. Ransom Note[easy] Given an arbitrary ransom note string and another string containing letters f ...

  5. 【LeetCode】383. Ransom Note 解题报告(Java & Python)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 [LeetCo ...

  6. leetcode修炼之路——383. Ransom Note

    题目是这样的 Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 a ...

  7. [LeetCode&Python] Problem 383. Ransom Note

    Given an arbitrary ransom note string and another string containing letters from all the magazines, ...

  8. 383. Ransom Note

    
Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
th ...

  9. [LeetCode] 383. Ransom Note_Easy tag: Hash Table

    Given an arbitrary ransom note string and another string containing letters from all the magazines, ...

随机推荐

  1. 【linux】su、sudo、sudo su、sudo -i的用法和区别

    来源:http://bbs.csdn.net/topics/390938651 sudo : 暂时切换到超级用户模式以执行超级用户权限,提示输入密码时该密码为当前用户的密码,而不是超级账户的密码.不过 ...

  2. whose view is not in the window hierarchy

    参考:http://www.jianshu.com/p/9e90cb866fdf 在做界面跳转的时候,我们经常会用到这两个函数 func dismissViewControllerAnimated(f ...

  3. TCP与UDP的区别

    TCP与UDP的区别 TCP面向连接:UDP是无连接,即发送数据之前不需要建立连接 TCP提供可靠的服务,TCP连接传送的数据,无差错.不丢失.不重复,且按顺序到达:UDP尽最大努力交付,即不保证可靠 ...

  4. 常用MIME类型(Flv,Mp4的mime类型设置)(转载)

    转载地址:http://www.cuplayer.com/player/Help/2011/0625/83.html 也许你会在纳闷,为什么我上传了flv或MP4文件到服务器,可输入正确地址通过htt ...

  5. jquery 事件冒泡的介绍以及如何阻止事件冒泡

    在一个对象上触发某类事件(比如单击onclick事件),如果此对象定义了此事件的处理程序,那么此事件就会调用这个处理程序,如果没有定义此事件处理程序或者事件返回true,那么这个事件会向这个对象的父级 ...

  6. Centos中文乱码的解决方法

    1)说明: Windows的默认编码为GBK,Linux的默认编码为UTF-8.在Windows下编辑的中文,在Linux下显示为乱码.为了解决此问题,修改Linux的默认编码为GBK. 2)查看支持 ...

  7. 廖雪峰js教程笔记13 插入DOM

    当我们获得了某个DOM节点,想在这个DOM节点内插入新的DOM,应该如何做? 如果这个DOM节点是空的,例如,<div></div>,那么,直接使用innerHTML = '& ...

  8. 首师大附中互测题:50229234海岛帝国:独立之战【C002】

    [C002]50229234海岛帝国:独立之战[难度C]———————————————————————————————————————————————————————————————————————— ...

  9. HDU-1203(01背包)

    I NEED A OFFER! Problem Description Speakless 很早就想出国,现在他已经考完了所有需要的考试,准备了所有要准备的材料,于是,便需要去申请学校了.要申请国外的 ...

  10. 2016中国大学生程序设计竞赛 - 网络选拔赛 C. Magic boy Bi Luo with his excited tree

    Magic boy Bi Luo with his excited tree Problem Description Bi Luo is a magic boy, he also has a migi ...