Safecracker

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 10165 Accepted Submission(s): 5213

Problem Description

=== Op tech briefing, 2002/11/02 06:42 CST ===

“The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with Klein and his factory, were destroyed in World War II. Fortunately old Brumbaugh from research knew Klein’s secrets and wrote them down before he died. A Klein safe has two distinguishing features: a combination lock that uses letters instead of numbers, and an engraved quotation on the door. A Klein quotation always contains between five and twelve distinct uppercase letters, usually at the beginning of sentences, and mentions one or more numbers. Five of the uppercase letters form the combination that opens the safe. By combining the digits from all the numbers in the appropriate way you get a numeric target. (The details of constructing the target number are classified.) To find the combination you must select five letters v, w, x, y, and z that satisfy the following equation, where each letter is replaced by its ordinal position in the alphabet (A=1, B=2, …, Z=26). The combination is then vwxyz. If there is more than one solution then the combination is the one that is lexicographically greatest, i.e., the one that would appear last in a dictionary.”

v - w^2 + x^3 - y^4 + z^5 = target

“For example, given target 1 and letter set ABCDEFGHIJKL, one possible solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are actually several solutions in this case, and the combination turns out to be LKEBA. Klein thought it was safe to encode the combination within the engraving, because it could take months of effort to try all the possibilities even if you knew the secret. But of course computers didn’t exist then.”

=== Op tech directive, computer division, 2002/11/02 12:30 CST ===

“Develop a program to find Klein combinations in preparation for field deployment. Use standard test methodology as per departmental regulations. Input consists of one or more lines containing a positive integer target less than twelve million, a space, then at least five and at most twelve distinct uppercase letters. The last line will contain a target of zero and the letters END; this signals the end of the input. For each line output the Klein combination, break ties with lexicographic order, or ‘no solution’ if there is no correct combination. Use the exact format shown below.”

Sample Input

1 ABCDEFGHIJKL

11700519 ZAYEXIWOVU

3072997 SOUGHT

1234567 THEQUICKFROG

0 END

Sample Output

LKEBA

YOXUZ

GHOST

no solution

一道简单的搜索题,但因为没有处理好,WA 了好几次

#include <iostream>
#include <cstring>
#include <cstdio>
#include <cmath> using namespace std; int len; bool vis[30]; char s[30]; int n; char str[30]; char Max[30]; void BFS(int num)
{
if(num==5)
{
str[5]='\0';
int m=str[0]-'A'+1-pow(str[1]-'A'+1,2)+pow(str[2]-'A'+1,3)-pow(str[3]-'A'+1,4)+pow(str[4]-'A'+1,5);
if(m==n)
{
if(strcmp(str,Max)>0)
{
strcpy(Max,str);
}
}
return ;
}
for(int i=0; i<len; i++)
{
if(!vis[i])
{
vis[i]=true;
str[num]=s[i];
BFS(num+1);
vis[i]=false;
}
}
}
int main()
{
while(scanf("%d %s",&n,s))
{
if(n==0&&strcmp(s,"END")==0)
break;
len=strlen(s);
memset(vis,false,sizeof(vis));
memset(Max,'\0',sizeof(Max));
BFS(0);
if(!strlen(Max))
{
printf("no solution\n");
}
else
{
printf("%s\n",Max);
}
}
return 0;
}

版权声明:本文为博主原创文章,未经博主允许不得转载。

Safecracker 分类: HDU 搜索 2015-06-25 21:12 12人阅读 评论(0) 收藏的更多相关文章

  1. android开发之调试技巧 分类: android 学习笔记 2015-07-18 21:30 140人阅读 评论(0) 收藏

    我们都知道,android的调试打了断点之后运行时要使用debug as->android application 但是这样的运行效率非常低,那么我们有没有快速的方法呢? 当然有. 我们打完断点 ...

  2. UI基础:UIButton.UIimage 分类: iOS学习-UI 2015-07-01 21:39 85人阅读 评论(0) 收藏

    UIButton是ios中用来响应用户点击事件的控件.继承自UIControl 1.创建控件 UIButton *button=[UIButton buttonWithType:UIButtonTyp ...

  3. UI基础:UITextField 分类: iOS学习-UI 2015-07-01 21:07 68人阅读 评论(0) 收藏

    UITextField 继承自UIControl,他是在UILabel基础上,对了文本的编辑.可以允许用户输入和编辑文本 UITextField的使用步骤 1.创建控件 UITextField *te ...

  4. hdu 5882 Balanced Game 2016-09-21 21:22 80人阅读 评论(0) 收藏

    Balanced Game Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) To ...

  5. 架构师速成5.1-小学gtd进阶 分类: 架构师速成 2015-06-26 21:17 313人阅读 评论(0) 收藏

    人生没有理想,那和咸鱼有什么区别. 有了理想如何去实现,这就是gtd需要解决的问题.简单说一下gtd怎么做? 确定你的目标,如果不能确定长期目标,至少需要一个2年到3年的目标. 目标必须是可以衡量的, ...

  6. 【solr专题之二】配置文件:solr.xml solrConfig.xml schema.xml 分类: H4_SOLR/LUCENCE 2014-07-23 21:30 1959人阅读 评论(0) 收藏

    1.关于默认搜索域 If you are using the Lucene query parser, queries that don't specify a field name will use ...

  7. Mahout快速入门教程 分类: B10_计算机基础 2015-03-07 16:20 508人阅读 评论(0) 收藏

    Mahout 是一个很强大的数据挖掘工具,是一个分布式机器学习算法的集合,包括:被称为Taste的分布式协同过滤的实现.分类.聚类等.Mahout最大的优点就是基于hadoop实现,把很多以前运行于单 ...

  8. Hiking 分类: 比赛 HDU 函数 2015-08-09 21:24 3人阅读 评论(0) 收藏

    Hiking Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total Subm ...

  9. Encoding 分类: HDU 2015-06-25 21:56 9人阅读 评论(0) 收藏

    Encoding Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Subm ...

  10. A Mathematical Curiosity 分类: HDU 2015-06-25 21:27 11人阅读 评论(0) 收藏

    A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Ot ...

随机推荐

  1. css less

    LESSCSS是一种动态样式语言,属于CSS预处理语言的一种,它使用类似CSS的语法,为CSS的赋予了动态语言的特性,如变量.继承.运算.函数等,更方便CSS的编写和维护. LESSCSS可以在多种语 ...

  2. C++Primer 第六章

    //1.我们通过调用运算符来执行函数.调用运算符的形式是一对圆括号,他作用于一个表达式,该表达式是一个函数或者指向函数的指针.圆括号之内是用逗号分隔的实参列表,用于初始化函数形参.调用表达式的类型就是 ...

  3. Swift实战-豆瓣电台(五)播放音乐

    观看地址 http://v.youku.com/v_show/id_XNzMwODM0MzI0.html 在这节里面,我们简单学习了一下MediaPlayer的使用 引入媒体框架 import Med ...

  4. lvs负载均衡的搭建

       lvs负载均衡的搭建 作者:尹正杰 版权声明:原创作品,谢绝转载!否则将追究法律责任.         在部署环境前,我们需要了解一下一些协议 一.什么是arp 地址解析协议,即ARP(Addr ...

  5. ACM/ICPC竞赛

    ACM知识点分类   第一类:基础算法 (1) 基础算法:枚举,贪心,递归,分治,递推,构造,模拟 (2) 动态规划:背包问题,树形dp,状态压缩dp,单调性优化,插头dp (3) 搜索:dfs,bf ...

  6. linux第5天 socket api

    IPv4套接口地址结构通常也称为“网际套接字地址结构”,它以“sockaddr_in”命名,定义在头文件<netinet/in.h>中 通用地址结构用来指定与套接字关联的地址.以socka ...

  7. String.Format数字格式化参考

    String.Format数字格式化输出 {0:N2} {0:D2} {0:C2} (转) 数字 {0:N2} 12.36 数字 {0:N0} 13 货币 {0:c2} $12.36 货币 {0:c4 ...

  8. webpack.config.js

    var webpack = require('webpack'); module.exports = { //插件项 plugins: [ new webpack.optimize.CommonsCh ...

  9. springmvc+spring+mybatis分页查询实例版本3,添加条件检索

    在第二个版本上添加了姓名模糊查询,年龄区间查询;自以为easy,结果发现mybatis的各种参数写法基本搞混或是忘了,zuo啊,直接上代码,然后赶紧把mybatis整理一遍再研究自己的项目,应该还会有 ...

  10. python函数传参是传值还是传引用?

    首先还是应该科普下函数参数传递机制,传值和传引用是什么意思? 函数参数传递机制问题在本质上是调用函数(过程)和被调用函数(过程)在调用发生时进行通信的方法问题.基本的参数传递机制有两种:值传递和引用传 ...