Formula Racing
Time Limit: 1000MS   Memory Limit: 30000K
Total Submissions: 289   Accepted: 77

Description

Background
The brand new formula racing team Irarref needs your help! Irarref
doesn't have any real good drivers but they want to dominate formula
racing. Since fairness doesn't mean anything to them they are trying to
build a fully automatic driving control which needs almost no driver
interaction.

Before actually trying the automatic driving control on track and
risking to crash their precious cars (they don't care much about their
drivers), they want to test it in a computer simulation.

Problem

You have to simulate the movement of a car on a given track. To
simplify the problem, cars can only move in 8 directions (horizontal,
vertical, and diagonal) on cells of a regular 2-dimensional grid, where
directions are encoded as follows:

701

6 2

543

Every turn the car executes exactly one of the following commands:

command description
move-on keep moving with the current speed and direction
accelerate increase the speed by 1
brake decrease the speed by 1 (does not go below 0!)
left turn 45 degrees left (decrease direction by 1)
right turn 45 degrees right (increase direction by 1)

In any case, a car moves its speed value in cells in its current
direction and crosses all cells in-between its old and new position.
When a car accelerates or brakes, its speed is adjusted before the
movement of the current turn. When a car turns, its direction is changed
before the movement.

The racing track is a 2-dimensional regular grid, where every cell
can be: road, non-road space (but still drivable), start/goal line (also
road and drivable), or wall.

Every car starts with an initial speed of 0 and has a maximum speed
which it cannot exceed. When a car hits non-road space its speed is
reduced to 1 in the next turn but it completes the move of this turn
with its current speed. When a car hits a wall it crashes, the
simulation stops immediately and there will be no next turn.

Every car is alone on the track, so you do not have to check for car/car collisions.

Input

The first line contains the number of scenarios.

For each scenario, the first line contains width w and height h of
the racing track (1 <= w, h <= 1000).The following h lines contain
the layout of the racing track where road, non-road-space, start/goal
line, and wall are represented by "x", ".", "s", and "W", respectively.
The upper left corner of the racing area is (0, 0), the lower right
corner (w-1, h-1), where coordinates are given as pairs (x, y) where
x-direction is horizontal and y-direction is vertical.

A line containing the number n of cars to simulate follows the track description. For every car there are two lines:

  • a line containing the initial x- and y-coordinate x and y,
    direction d, and maximum speed m of the car, as integers separated by
    single blanks, where 0 <= x <= w-1, 0 <= y <= h-1, 0 <= d
    <= 7, 1 <= m
  • a line containing a string whose single characters each
    encode one command for this car, where "m","a", "b", "l", and "r"
    represent move-on, accelerate, brake, left, and right, respectively; the
    number of commands for a car is at least 1 and at most 10000.

It is guaranteed that the initial car position is not on a wall. It
is also guaranteed that the car does not leave the track area without
crashing.

Output

The
output for every scenario begins with a line containing "Scenario #i:",
where i is the number of the scenario starting at 1. For every scenario
print for ever car the following information:

  • If the car did not crash print a line containing the final
    position (x- and y-coordinate), direction and speed of the car, all
    separated by single spaces.If the car did crash print a line containing
    the crash-point (x- and y-coordinate), direction and speed of the car at
    the moment of the crash and the word "crashed", all separated by single
    spaces.
  • For every hit of a start/goal field (a hit is counted when
    moving onto a start/goal field) print a line beginning with "crossing
    startline:", followed by a single space, the x- and
    y-coordinates,direction, speed and the number of the simulation turn the
    line was crossed or hit. The lines must be printed in the same order
    the start/goal fields were hit.

Print a blank line after each scenario.

Sample Input

1
12 12
WWWWWWWWWWWW
W...xxxx...W
W..xxxxxx..W
W.xxWWWWxx.W
WxxWW..WWxxW
WxxW....WxxW
WssW....WxxW
WxxWW..WWxxW
W.xxWWWWxx.W
W..xxxxxx..W
W...xxxx...W
WWWWWWWWWWWW
2
1 6 0 3
armmrarrmrrrbrmmb
1 5 0 4
ararmrramrmar

Sample Output

Scenario #1:
2 4 0 0
crossing startline: 2 6 0 1 13
5 11 5 2 crashed

Source

TUD Programming Contest 2004, Darmstadt, Germany

[Submit]   [Go Back]   [Status]   [Discuss]

英文阅读题。1h读懂题,10min写完。

纯模拟,看网上没有代码就发一份吧。

 #include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std; const int N=;
int n,m,T,mx,tot,times,x,y,d,mn,speed,len;
char op[N],mp[N][N];
const int dx[]={,,,,,-,-,-},dy[]={-,-,,,,,,-};
struct P{ int x,y,d,speed,id; }p[N*N]; void up(int &x){ if (x<mx) x++; }
void dn(int &x){ if (x) x--; } int main(){
scanf("%d",&T);
for (int cas=; cas<=T; cas++){
scanf("%d%d",&n,&m); printf("Scenario #%d:\n",cas);
for (int i=; i<n; i++) scanf("%s",mp[i]);
scanf("%d",&times);
for (int tt=; tt<times; tt++){
scanf("%d%d%d%d",&x,&y,&d,&mx);
speed=tot=; bool cr=;
scanf("%s",op); len=strlen(op);
for (int i=; i<len; i++){
if (op[i]=='a') up(speed);
if (op[i]=='b') dn(speed);
if (op[i]=='l') d=(d+)%;
if (op[i]=='r') d=(d+)%;
bool flag=;
for (int j=; j<speed; j++){
x+=dx[d]; y+=dy[d];
if (mp[y][x]=='.') flag=;
if (mp[y][x]=='W') { printf("%d %d %d %d crashed\n",x,y,d,speed); cr=; break; }
if (mp[y][x]=='s') p[tot++]=(P){x,y,d,speed,i};
}
if (flag) speed=;
if (cr) break;
}
if (!cr) printf("%d %d %d %d\n",x,y,d,speed);
for (int i=; i<tot; i++) printf("crossing startline: %d %d %d %d %d\n",p[i].x,p[i].y,p[i].d,p[i].speed,p[i].id);
}
puts("");
}
return ;
}

[POJ1801]Formula Racing(模拟)的更多相关文章

  1. POJ 3672 Long Distance Racing (模拟)

    题意:给定一串字符,u表示是上坡,d表示下坡,f表示平坦的,每个有不同的花费时间,问你从开始走,最远能走到. 析:直接模拟就好了,没什么可说的,就是记下时间时要记双倍的,因为要返回来的. 代码如下: ...

  2. PKUSC2018训练日程(4.18~5.30)

    (总计:共66题) 4.18~4.25:19题 4.26~5.2:17题 5.3~5.9: 6题 5.10~5.16: 6题 5.17~5.23: 9题 5.24~5.30: 9题 4.18 [BZO ...

  3. HOJ题目分类

    各种杂题,水题,模拟,包括简单数论. 1001 A+B 1002 A+B+C 1009 Fat Cat 1010 The Angle 1011 Unix ls 1012 Decoding Task 1 ...

  4. Lucky and Good Months by Gregorian Calendar - POJ3393模拟

    Lucky and Good Months by Gregorian Calendar Time Limit: 1000MS Memory Limit: 65536K Description Have ...

  5. (转) Deep Reinforcement Learning: Playing a Racing Game

    Byte Tank Posts Archive Deep Reinforcement Learning: Playing a Racing Game OCT 6TH, 2016 Agent playi ...

  6. HDUOJ-------1052Tian Ji -- The Horse Racing(田忌赛马)

    Tian Ji -- The Horse Racing Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (J ...

  7. poj1472[模拟题]

    Instant Complexity Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 2017   Accepted: 698 ...

  8. HDU 5912 Fraction 【模拟】 (2016中国大学生程序设计竞赛(长春))

    Fraction Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Su ...

  9. HUNNU11342:Chemistry(模拟)

    http://acm.hunnu.edu.cn/online/?action=problem&type=show&id=11342 Problem description The ch ...

随机推荐

  1. 【luogu 1439 最长公共子序列】

    题目描述 给出1-n的两个排列P1和P2,求它们的最长公共子序列. 输入输出格式 输入格式: 第一行是一个数n, 接下来两行,每行为n个数,为自然数1-n的一个排列. 输出格式: 一个数,即最长公共子 ...

  2. android OTA升级包制作

    0.签名 java -Xmx2048m -jar out/host/linux-x86/framework/signapk.jar -w build/target/product/security/t ...

  3. 自定义toolbar教程

    1.写toolbar的布局文件 ,toolbar.xml <?xml version="1.0" encoding="utf-8"?> <Re ...

  4. i=i+1与i+=1的区别及效率(Java)

    原博客地址 在做个java优化的PPT时,看到了i=i+1与i+=1的区别,在这之前还真没想到那么细. 1.x=x+1,x+=1及x++的效率哪个最高?为什么? x=x+1最低,因为它的执行如下. ( ...

  5. css3中-moz、-ms、-webkit分别代表的意思

    这三个分别是目前流行的三种浏览器的私有属性 -moz代表firefox浏览器私有属性 -ms代表ie浏览器私有属性(360浏览器是ie内核) -webkit代表safari.chrome私有属性 -o ...

  6. vue+koa+mysql简易demo

    功能支持网址收藏编辑 代码: https://github.com/lanleilin/lanOdyssey/tree/master/vueKoa/webCollection1 运行方法: 在serv ...

  7. iconfont字体图标

    1.1.进入阿里图标网站 http://www.iconfont.cn/ 1.2.在购物车里添加自己需要的字体图标 1.3.下载代码 1.4.解压过后,找到iconfont.css,放在你的项目里,需 ...

  8. Android百度地图的使用

    做关于位置或者定位的app的时候免不了使用地图功能,本人最近由于项目的需求需要使用百度地图的一些功能,所以这几天研究了一下,现写一下blog记录一下,欢迎大家评论指正! 一.申请AK(API Key) ...

  9. Lucene4.6查询时完全跳过打分,提高查询效率的实现方式

    由于索引的文件量比较大,而且应用中不需要对文档进行打分,只需要查询出所有满足条件的文档.所以需要跳过打分来提高查询效率.一开始想用ConstantScoreQuery,但是测试发现这个类虽然让所有返回 ...

  10. codeforces613B - Skills &&金中市队儿童节常数赛

    题目传送门 本随笔写的是第二题...... 这道题方法就是搞乱....因为n较mxa小 所以枚举达到最大上限的点 然后就乱搞 代码看看咯 #include<cstdio> #include ...