HDU 4725 The Shortest Path in Nya Graph
he Shortest Path in Nya Graph
This problem will be judged on HDU. Original ID: 4725
64-bit integer IO format: %I64d Java class name: Main
The Nya graph is an undirected graph with "layers". Each node in the graph belongs to a layer, there are N nodes in total.
You can move from any node in layer x to any node in layer x + 1, with cost C, since the roads are bi-directional, moving from layer x + 1 to layer x is also allowed with the same cost.
Besides, there are M extra edges, each connecting a pair of node u and v, with cost w.
Help us calculate the shortest path from node 1 to node N.
Input
For each test case, first line has three numbers N, M (0 <= N, M <= 105) and C(1 <= C <= 103), which is the number of nodes, the number of extra edges and cost of moving between adjacent layers.
The second line has N numbers li (1 <= li <= N), which is the layer of ith node belong to.
Then come N lines each with 3 numbers, u, v (1 <= u, v < =N, u <> v) and w (1 <= w <= 104), which means there is an extra edge, connecting a pair of node u and v, with cost w.
Output
If there are no solutions, output -1.
Sample Input
2
3 3 3
1 3 2
1 2 1
2 3 1
1 3 3 3 3 3
1 3 2
1 2 2
2 3 2
1 3 4
Sample Output
Case #1: 2
Case #2: 3
Source
#include <bits/stdc++.h>
#define pii pair<int,int>
using namespace std;
const int INF = 0x3f3f3f3f;
const int maxn = ;
struct arc{
int to,w,next;
arc(int x = ,int y = ,int z = -){
to = x;
w = y;
next = z;
}
}e[];
int head[maxn],d[maxn],tot,n,m,c;
int layer[maxn];
void add(int u,int v,int w){
e[tot] = arc(v,w,head[u]);
head[u] = tot++;
}
bool done[maxn];
priority_queue< pii,vector< pii >,greater< pii > >q;
int dijkstra(int s,int t){
while(!q.empty()) q.pop();
memset(d,0x3f,sizeof d);
memset(done,false,sizeof done);
q.push(pii(d[s] = ,s));
while(!q.empty()){
int u = q.top().second;
q.pop();
if(done[u]) continue;
done[u] = true;
for(int i = head[u]; ~i; i = e[i].next){
if(d[e[i].to] > d[u] + e[i].w){
d[e[i].to] = d[u] + e[i].w;
q.push(pii(d[e[i].to],e[i].to));
}
} }
return d[t] == INF?-:d[t];
}
bool hslv[maxn];
int main(){
int kase,tmp,u,v,w,cs = ;
scanf("%d",&kase);
while(kase--){
memset(head,-,sizeof head);
memset(hslv,false,sizeof hslv);
tot = ;
scanf("%d%d%d",&n,&m,&c);
for(int i = ; i <= n; ++i){
scanf("%d",&tmp);
layer[i] = tmp;
hslv[tmp] = true;
}
for(int i = ; i < m; ++i){
scanf("%d%d%d",&u,&v,&w);
add(u,v,w);
add(v,u,w);
}
for(int i = ; i <= n; ++i){
add(layer[i]+n,i,);
if(layer[i] > ) add(i,layer[i]-+n,c);
if(layer[i] < n) add(i,layer[i]+n+,c);
}
printf("Case #%d: %d\n",cs++,dijkstra(,n));
}
return ;
}
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