golang slice切片的原理以及内置函数cap, len

golang中slice(切片)是常用的类型, slice是对数组进行封装

package main

import (   "fmt"   "strconv")

func testLenCap() {   strs := make([]string, 5, 10) //可以只有一个数字参数, 那么cap=len, make([]string, 5, 5) 等价于 make([]string, 5)   fmt.Printf("value=%v, is nil=%v\n", strs, strs == nil)   //strs := []string{"0", "1", "2", "3", "4"} //当然这种方式是直接赋值了, 忽略赋值等价于 make([]string, 5)

   for i := 0; i < len(strs); i++ {      strs[i] = strconv.Itoa(i)   }   fmt.Printf("len=%v, cap=%v, strsAddress=%p, valueAddress=%p\n", len(strs), cap(strs), &strs, strs) //%p内存地址

   for i := len(strs); i < cap(strs); i++ {      //strs[i] = strconv.Itoa(i) //panic      strs = append(strs, strconv.Itoa(i)) //使用append向数组追加数据   }   fmt.Printf("len=%v, cap=%v, strsAddress=%p, valueAddress=%p\n", len(strs), cap(strs), &strs, strs) //内存地址不变

   strs = append(strs, "10")   fmt.Printf("len=%v, cap=%v, strsAddress=%p, valueAddress=%p\n", len(strs), cap(strs), &strs, strs) //内存地址改变

   //strs2自身的地址与strs不一样, 但实际数组的内存地址不变, 改变strs, strs2其中任意一个变量, 另一个随之改变   strs2 := strs[:]   fmt.Printf("len=%v, cap=%v, strsAddress=%p, valueAddress=%p\n", len(strs2), cap(strs2), &strs2, strs2)   strs2[5] = "1000"   fmt.Printf("strs[5]=%s\n", strs[5])

   //strs3自身的地址与strs不一样, 实际数组的内存地址也不一样, 互不干扰.   startIndex := 5   strs3 := strs[startIndex:7]   fmt.Printf("len=%v, cap=%v, strsAddress=%p, valueAddress=%p\n", len(strs3), cap(strs3), &strs3, strs3)   fmt.Printf("cap(strs3) == cap(strs)-startIndex : %v", cap(strs3) == cap(strs)-startIndex)}

func main() {   testLenCap()

}

控制台打印结果:

value=[ ], is nil=false
len=5, cap=10, strsAddress=0xc0420023e0, valueAddress=0xc04203e0a0
len=10, cap=10, strsAddress=0xc0420023e0, valueAddress=0xc04203e0a0
len=11, cap=20, strsAddress=0xc0420023e0, valueAddress=0xc042040140
len=11, cap=20, strsAddress=0xc0420024a0, valueAddress=0xc042040140
strs[5]=1000
len=2, cap=15, strsAddress=0xc0420024e0, valueAddress=0xc042040190
cap(strs3) == cap(strs)-startIndex : true

可以看到:

len函数是实际数据存长度;

cap是最大容量,可以避免反复分配内存;

扩容机制是翻倍, 所以go的扩容很快, 尤其是基数很大的情况下.  但如果能预先分配cap, 即使再快也是无畏的消耗

使用原切片创建新切片时, 应注意每个切片的值, 避免出现与预想不一样的情况