leetcode 155. Min Stack --------- java
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- getMin() -- Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> Returns -3.
minStack.pop();
minStack.top(); --> Returns 0.
minStack.getMin(); --> Returns -2.
设计一个可以获得最小值的栈。
第一次用了ArrayList和Stack,超时了。
public class MinStack {
Stack<Integer> stack ;
ArrayList<Integer> list;
public MinStack() {
stack = new Stack<Integer>();
list = new ArrayList<Integer>();
}
public void push(int x) {
stack.push(x);
int flag = 0;
if( list.size() == 0 ){
list.add(x);
return ;
}
for( int i = 0 ; i < list.size() && flag == 0;i++){
if( list.get(i) > x ){
list.add(i,x);
flag = 1;
}
}
if( flag == 0)
list.add(list.size(),x);
}
public void pop() {
list.remove((Integer) stack.pop());
}
public int top() {
return stack.peek();
}
public int getMin() {
return list.get(0);
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
只使用一个ArrayList
public class MinStack {
ArrayList<Integer> list;
int min ;
public MinStack() {
list = new ArrayList<Integer>();
}
public void push(int x) {
list.add(x);
if( list.size() == 1)
min = x;
else
min = Math.min(min,x);
}
public void pop() {
list.remove( list.size()-1 );
if( list.size() == 0)
return ;
min = list.get(0);
for( int i = 1 ; i < list.size();i++)
min = Math.min(min,list.get(i));
}
public int top() {
return list.get(list.size()-1);
}
public int getMin() {
return min;
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
3、使用两个栈实现。
public class MinStack {
private Stack<Integer> stack = new Stack<Integer>();
// minStack: store the current min values
private Stack<Integer> minStack = new Stack<Integer>();
public void push(int x) {
// store current min value into minStack
if (minStack.isEmpty() || x <= minStack.peek())
minStack.push(x);
stack.push(x);
}
public void pop() {
// use equals to compare the value of two object, if equal, pop both of them
if (stack.peek().equals(minStack.peek()))
minStack.pop();
stack.pop();
}
public int top() {
return stack.peek();
}
public int getMin() {
return minStack.peek();
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
4、也可以只用一个栈实现。
public class MinStack {
long min;
Stack<Long> stack;
public MinStack(){
stack=new Stack<>();
}
public void push(int x) {
if (stack.isEmpty()){
stack.push(0L);
min=x;
}else{
stack.push(x-min);//Could be negative if min value needs to change
if (x<min) min=x;
}
}
public void pop() {
if (stack.isEmpty()) return;
long pop=stack.pop();
if (pop<0) min=min-pop;//If negative, increase the min value
}
public int top() {
long top=stack.peek();
if (top>0){
return (int)(top+min);
}else{
return (int)(min);
}
}
public int getMin() {
return (int)min;
}
}
5、不用栈实现。
class MinStack {
private Node head;
public void push(int x) {
if(head == null)
head = new Node(x, x);
else
head = new Node(x, Math.min(x, head.min), head);
}
public void pop() {
head = head.next;
}
public int top() {
return head.val;
}
public int getMin() {
return head.min;
}
private class Node {
int val;
int min;
Node next;
private Node(int val, int min) {
this(val, min, null);
}
private Node(int val, int min, Node next) {
this.val = val;
this.min = min;
this.next = next;
}
}
}
leetcode 155. Min Stack --------- java的更多相关文章
- leetcode 155. Min Stack 、232. Implement Queue using Stacks 、225. Implement Stack using Queues
155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } v ...
- Java [Leetcode 155]Min Stack
题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant ti ...
- LeetCode 155 Min Stack(最小栈)
翻译 设计支持push.pop.top和在常量时间内检索最小元素的栈. push(x) -- 推送元素X进栈 pop() -- 移除栈顶元素 top() -- 得到栈顶元素 getMin() -- 检 ...
- Java for LeetCode 155 Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. pu ...
- [LeetCode] 155. Min Stack 最小栈
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. pu ...
- Leetcode 155 Min Stack 小顶堆+栈,优先队列实现 难度:0
https://leetcode.com/problems/min-stack/ #include <vector> #include <queue> #include < ...
- Leetcode 155 Min Stack
题意:设计一个能输出栈内最小值的栈 该题设计两个栈,一个栈是正常的栈s,而另一个是存最小值的栈sm 在push时要判断sm是否为空,如果为空或者非空但是栈顶元素大于等于插入值的 需要在sm中插入x 同 ...
- 155. Min Stack
题目: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time ...
- [LeetCode] 0155. Min Stack 最小栈 & C++Runtime加速
题目 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. ...
随机推荐
- 结对编程——关于Fault、Error、Failure程序设计
一.问题描述: 构造程序,分别是: •不能触发Fault •触发Fault,但是不能触发Error •触发Error,但是不能产生Fai ...
- java基础之 http
HTTP(HyperText Transfer Protocol)是一套计算机通过网络进行通信的规则.计算机专家设计出HTTP,使HTTP客户(如Web浏览器)能够从HTTP服务器(Web服务器)请求 ...
- vSphere Client上传镜像
1. 使用vSphere Client连接到VMware ESXI 2. 打开右侧 [摘要] 选项卡 3. 在 [资源] 中选择存储器中的存储,右键 [浏览数据库存储] 4. 选择工具栏 [创建新文件 ...
- git——学习笔记(一)
http://www.liaoxuefeng.com/wiki/0013739516305929606dd18361248578c67b8067c8c017b000/0013745374151782e ...
- NorFlash和NandFlash区别
Flash编程原理都是只能将1写为0,而不能将0写成1.所以在Flash编程之前,必须将对应的块擦除,而擦除的过程就是将所有位都写为1的过程,块内的所有字节变为0xFF.因此可以说,编程是将相应位 ...
- 0911 Socket网络编程
1.实现ftp上传.下载功能 1.1 循环接收数据直到接收完毕 server端接收client发送的命令(比如说ifconfig),然后server端将命令执行结果反馈给客户端,这时候有个问题,ser ...
- 使用busybox构建根文件系统
当我们在Qemu上运行起来自己编译的内核之后,需要使用busybox构建一个文件系统,将此文件系统挂载上去就可以使用busybox提供的各种命令了. 1.编译安装busybox 源码下载地址:http ...
- python的循环语句等
names = ['Michael', 'Bob', 'Tracy'] for name in names: print name sum = 0 for x in [1, 2, 3, 4, 5, 6 ...
- linux常用命令:1文件处理命令
文件处理命令 1.命令格式 命令格式:命令 [-选项] [参数] 例:ls -la /etc 说明:1)个别命令使用不遵循此格式 2)档有多个选项时,可以写在一起 3)简化选项与完整选项 2.目录 ...
- 日历控件修改的JS代码
var bMoveable=true; var _VersionInfo=" " ; //============================================= ...