poj2429 GCD & LCM Inverse
用miller_rabin 和 pollard_rho对大数因式分解,再用dfs寻找答案即可。
http://poj.org/problem?id=2429
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;
typedef __int64 LL;
const int maxn = ;
const int times = ;
LL prime[maxn], k;
int cnt[maxn];
LL c, d, pm, mid; void dfs(int pos, LL t){
if(pos == k){
if(pm < t) pm = t;
return;
}
LL tem = ;
int c = cnt[pos];
while(c--) tem *= prime[pos];
dfs(pos + , t);
if(t * tem <= mid) dfs(pos + , t * tem);
} LL random(LL n){
return (double)rand() / RAND_MAX * n + 0.5;
} LL multi(LL a, LL b, LL mod){
a %= mod, b %= mod;
LL ans = ;
while(b){
if(b & ) ans += a, ans %= mod;
b >>= ;
a <<= ;
a %= mod;
}
return ans;
} LL power(LL a, LL p, LL mod){
a %= mod;
LL ans = ;
while(p){
if(p & ) ans = multi(ans, a, mod), ans %= mod;
p >>= ;
a = multi(a, a, mod);
a %= mod;
}
return ans;
} LL gcd(LL a, LL b){
if(!b) return a;
return gcd(b, a % b);
} bool witness(LL a, LL n){
LL u = n - ;
while(!(u & )) u >>= ;
LL t = power(a, u, n);
while(u != n - && t != && t != n - ){
t = multi(t, t, n);
u <<= ;
}
return t == n - || u & ;
} bool miller_rabin(LL n){
if(n == ) return ;
if(n < || !(n & )) return ;
for(int i = ; i < times; i++){
LL p = random(n - ) + ;
if(!witness(p, n)) return ;
}
return ;
} LL pollard_rho(LL n, LL t){
LL x = random(n - ) + ;
LL y = x, i = , k = , d;
while(){
++i;
x = (multi(x, x, n) + t) % n;
d = gcd(y - x, n);
if( < d && d < n) return d;
if(x == y) return n;
if(i == k){
y = x;
k <<= ;
}
}
} void solve(){
LL m = d / c;
LL m1 = m;
mid = (LL)sqrt(m);
k = ;
memset(cnt, , sizeof cnt);
if(m % == ){
prime[k++] = ;
while(m % == ) m >>= , ++cnt[k - ];
}
while(!miller_rabin(m) && m > ){
int seed = ;
LL p1 = m;
while(p1 >= m || !miller_rabin(p1)) p1 = pollard_rho(m, seed--);
prime[k++] = p1;
while(m % p1 == ) m /= p1, ++cnt[k - ];
}
if(m != ) prime[k++] = m, ++cnt[k - ];
pm = ;
dfs(, );
LL qm = m1 / pm;
printf("%I64d %I64d\n", pm * c, qm * c);
} int main(){
//freopen("in.txt", "r", stdin);
//freopen("out.txt", "w", stdout);
while(~scanf("%I64d%I64d", &c, &d)) solve();
return ;
}
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