UVa 107 - The Cat in the Hat (找规律,注意精度)
| The Cat in the Hat |
Background
(An homage to Theodore Seuss Geisel)
The Cat in the Hat is a nasty creature,
But the striped hat he is wearing has a rather nifty feature.
With one flick of his wrist he pops his top off.
Do you know what's inside that Cat's hat?
A bunch of small cats, each with its own striped hat.
Each little cat does the same as line three,
All except the littlest ones, who just say ``Why me?''
Because the littlest cats have to clean all the grime,
And they're tired of doing it time after time!
The Problem
A clever cat walks into a messy room which he needs to clean. Instead of doing the work alone, it decides to have its helper cats do the work. It keeps its (smaller) helper cats inside its hat. Each helper cat also has helper cats in its own hat, and so on. Eventually, the cats reach a smallest size. These smallest cats have no additional cats in their hats. These unfortunate smallest cats have to do the cleaning.
The number of cats inside each (non-smallest) cat's hat is a constant, N. The height of these cats-in-a-hat is
times the height of the cat whose hat they are in.
The smallest cats are of height one;
these are the cats that get the work done.
All heights are positive integers.
Given the height of the initial cat and the number of worker cats (of height one), find the number of cats that are not doing any work (cats of height greater than one) and also determine the sum of all the cats' heights (the height of a stack of all cats standing one on top of another).
The Input
The input consists of a sequence of cat-in-hat specifications. Each specification is a single line consisting of two positive integers, separated by white space. The first integer is the height of the initial cat, and the second integer is the number of worker cats.
A pair of 0's on a line indicates the end of input.
The Output
For each input line (cat-in-hat specification), print the number of cats that are not working, followed by a space, followed by the height of the stack of cats. There should be one output line for each input line other than the ``0 0'' that terminates input.
Sample Input
216 125
5764801 1679616
0 0
Sample Output
31 671
335923 30275911
解题思路:
帽子里的猫,
此题给的条件是第一支猫的高度h和最后的working cats的数量w.
下面分析猫的高度和猫的数量之间的关系:
设开始的猫的高度是 h , N 是每个帽子里面猫的数量,设一个中间变量s。
猫的高度 h h / (N + 1) h / (N + 1)2 ………… h / (N + 1)s
猫的数量 1 N N * N ………… Ns
当最后工作的猫的个数为w时:
lg(n)/lg(n+1)=lg(num)/lg(hgiht)
是用二分查找算出N即可,条件就写成了fabs(lg(n)*lg(height)-lg(num)/lg(n+1)<0.00001)
下面贴代码:
#include <bits/stdc++.h> using namespace std; int main()
{
int h,num;
while(~scanf("%d%d",&h,&num))
{
if(==h&&==num)
break;
int left=,right=,mid;
while(left)
{
mid=(left+right)/;
if(fabs(log(mid)*log(h)-log(mid+)*log(num))<=0.000001) break;
if(log(mid)*log(h)-log(mid+)*log(num)>)
right=mid;
else
left=mid;
}
int x=,y=h;
left=;
while(h>)
{
h/=(+mid);
left*=mid;
x+=left;
y+=h*left;
}
printf("%d %d\n",x-num+,y);
}
}
UVa 107 - The Cat in the Hat (找规律,注意精度)的更多相关文章
- uva 107 - The Cat in the Hat
The Cat in the Hat Background (An homage to Theodore Seuss Geisel) The Cat in the Hat is a nasty c ...
- 杂题 UVAoj 107 The Cat in the Hat
The Cat in the Hat Background (An homage to Theodore Seuss Geisel) The Cat in the Hat is a nasty c ...
- UVA - 808 Bee Breeding (建立坐标系&找规律)
题目: 输入两个格子的编号a和b(a,b≤10000),求最短距离.例如,19和30的距离为5(一条最短路是19-7-6-5-15-30). 思路: 如图建立坐标系,然后看两个点的向量如果位于二四象限 ...
- 【数论,找规律】Uva 11526 - H(n)
原来做过的题再看还是没想出来,看来当时必然没有真正理解.这次回顾感觉理解更透彻了. 网上的题解差不多都是一个版本,而且感觉有点扯.根据n=20猜出来的? 好吧哪能根据一个就猜到那么变态的公式.其实这题 ...
- GCD XOR UVA 12716 找规律 给定一个n,找多少对(a,b)满足1<=b<=a<=n,gcd(a,b)=a^b;
/** 题目:GCD XOR UVA 12716 链接:https://vjudge.net/problem/UVA-12716 题意:给定一个n,找多少对(a,b)满足1<=b<=a&l ...
- 递推+高精度+找规律 UVA 10254 The Priest Mathematician
题目传送门 /* 题意:汉诺塔问题变形,多了第四个盘子可以放前k个塔,然后n-k个是经典的汉诺塔问题,问最少操作次数 递推+高精度+找规律:f[k]表示前k放在第四个盘子,g[n-k]表示经典三个盘子 ...
- SGU 107 987654321 problem【找规律】
题目链接: http://acm.sgu.ru/problem.php?contest=0&problem=107 题意: 平方后几位为987654321的n位数有多少个 分析: 虽然说是水题 ...
- UVa 11774 (置换 找规律) Doom's Day
我看大多数人的博客只说了一句:找规律得答案为(n + m) / gcd(n, m) 不过神题的题解还须神人写.. We can associate at each cell a base 3-numb ...
- UVA 10254 - The Priest Mathematician (dp | 汉诺塔 | 找规律 | 大数)
本文出自 http://blog.csdn.net/shuangde800 题目点击打开链接 题意: 汉诺塔游戏请看 百度百科 正常的汉诺塔游戏是只有3个柱子,并且如果有n个圆盘,至少需要2^n- ...
随机推荐
- asp.net url重写相关技术问题整理
1.IIS7配置URL重写需要注意系统是32位还是64位的 在IIS7配置URL重写的时候,需要添加“脚本映射”,如果是64位系统,会有两个地方存放.net framework分别是32位系统和64位 ...
- 【推荐】oc解析HTML数据的类库(爬取网页数据)
TFhpple是一个用于解析html数据的第三方库,本人感觉功能还算可以,只不过在使用前必须配置项目. 配置 1.导入libxml2.tbd 2.设置编译路径 使用 这里使用一个例子来说明 http: ...
- AC自动机 - 多模式串匹配问题的基本运用 + 模板题 --- HDU 2222
Keywords Search Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)T ...
- Ubuntu系统操作快捷键
Ubuntu操作基本快捷键* 打开主菜单 = Alt + F1* 运行 = Alt + F2* 显示桌面 = Ctrl + Alt + d* 最小化当前窗口 = Alt + F9* 最大化当前窗口 = ...
- php查询IP地址归属等信息
淘宝公司提供了一个很好用的IP地理信息查询接口.在这里:http://ip.taobao.com/TaobaoIPQuery2这个类将极大的简化相关的信息查询. 类 TaobaoIPQuery2 文件 ...
- out 和 ref 参数修饰符
整理自MSDN out: out 关键字通过引用传递参数.这与 ref 关键字相似,只不过 ref 要求在传递之前初始化变量.若要使用 out 参数,方法定义和调用方法均必须显式使用 out 关键字. ...
- 【jQuery基础学习】05 jQuery与Ajax以及序列化
好吧,这章不像上章那么水了,总是炒剩饭也不好. 关于AJAX 所谓Ajax,全名Asynchronous JavaScript and XML.(也就异步的JS和XML) 简单点来讲就是不刷新页面来发 ...
- 重新想象 Windows 8 Store Apps (44) - 多线程之异步编程: 经典和最新的异步编程模型, IAsyncInfo 与 Task 相互转换
[源码下载] 重新想象 Windows 8 Store Apps (44) - 多线程之异步编程: 经典和最新的异步编程模型, IAsyncInfo 与 Task 相互转换 作者:webabcd 介绍 ...
- 字符串中Emoji表情处理
吃了经验的亏,因为Emoji表情引起的项目bug被撸主遇到两次了,总有一些调皮的小朋友爱用表情来搞点事.第一次把当时那个表改为utf8mb4解决了,第二次说啥都不好使.网上找了半天,发现好多人不去实验 ...
- Java文件编码自动转换工具类(只改变编码,不会改变文件内容)
本篇随笔主要介绍了一个用java语言写的将一个文件编码转换为另一个编码并不改变文件内容的工具类: 通过读取源文件内容,用URLEncoding重新编码解码的方式实现. public class Cha ...