用正则验证字符串格式，形如:A)XXX B)XXXX C)XXX

今天遇到个小功能，要验证某个英文选项是否正确，例如：A)accumulate B)circling C)communities  D)competition  E)domestic F)financially G)formally  H)gather  I)households  J)recession  K)reported L)reviewed M)serves N)surrounding O)survive

要求：1.必须按顺序排下来,ABCD....

　　　2.选项后代英文)

符合格式则返回true,不符合则为false

想了想，还是用正则先分成一个字符串数组，每个元素即每个单选项，所以就顺手写了下，发现很简单也蛮有趣的：

 using System;
 using System.Collections.Generic;
 using System.Linq;
 using System.Text;
 using System.Text.RegularExpressions;

 namespace ConsoleApplication1
 {
     class Program
     {
         static void Main(string[] args)
         {
             Console.WriteLine(Check(@"A)accumulate B)circling C)communities  D)competition  E)domestic
                                       F)financially G)formally  H)gather  I)households  J)recession  "));
             Console.WriteLine(Check(@"A|accumulate B)circling C)communities  D)competition"));
             Console.WriteLine(Check(@"A)accumulate C)communities  D)competition"));
             Console.WriteLine(Check(@"A|accumulate"));
             Console.WriteLine(Check(@""));

             Console.Read();

             //输出结果
             //true
             //false
             //false
             //false
             //false
         }

         public static bool Check(string options)
         {
             MatchCollection mc = Regex.Matches(options,@"[A-Z]\)[^A-Z]*");  //匹配A)XXX，直到下一个A)
             //没匹配到，直接返回false
             if (mc.Count == )
             {
                 return false;
             }
             //匹配到，继续检验
             else
             {
                 char c = 'A';
                 string bracket = ")";
                 foreach (Match option in mc)
                 {
                     //形如A)
                     string tmp = c + bracket;
                     if (!option.Value.Contains(tmp))
                         return false;
                     //A自增为B
                     c++;
                 }
                 return true;
             }

         }
     }
 }

务必引用c#的正则库函数：  using System.Text.RegularExpressions;