The 2018 ACM-ICPC Chinese Collegiate Programming Contest Take Your Seat
/*
证明过程如下 :
第一种情况:
按1到n的顺序上飞机,1会随意选一个,剩下的上去时若与自己序号相同的
座位空就坐下去,若被占了就也会随意选一个。
求最后一个人坐在应坐位置的概率
*/



#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <algorithm>
#include <utility>
#include <vector>
#include <map>
#include <queue>
#include <stack>
#include <cstdlib>
typedef long long ll;
#define lowbit(x) (x&(-x))
#define ls l,m,rt<<1
#define rs m+1,r,rt<<1|1
using namespace std;
double x=0.5;
double y=1.0;
int main()
{
int t,n,m;
scanf("%d",&t);
for(int i=;i<=t;i++)
{
scanf("%d%d",&n,&m);
if(n==){//特判
printf("Case #%d: %.6f %.6f\n",i,y,1.0*(m+)/(*m));
}
else{
printf("Case #%d: %.6f %.6f\n",i,x,1.0*(m+)/(*m));
}
}
return ;
}
The 2018 ACM-ICPC Chinese Collegiate Programming Contest Take Your Seat的更多相关文章
- ACM ICPC, JUST Collegiate Programming Contest (2018) Solution
A:Zero Array 题意:两种操作, 1 p v 将第p个位置的值改成v 2 查询最少的操作数使得所有数都变为0 操作为可以从原序列中选一个非0的数使得所有非0的数减去它,并且所有数不能 ...
- ACM ICPC, Amman Collegiate Programming Contest (2018) Solution
Solution A:Careful Thief 题意:给出n个区间,每个区间的每个位置的权值都是v,然后找长度为k的区间,使得这个区间的所有位置的权值加起来最大,输出最大权值, 所有区间不重叠 思路 ...
- The 2018 ACM-ICPC Chinese Collegiate Programming Contest Moving On
Firdaws and Fatinah are living in a country with nn cities, numbered from 11 to nn.Each city has a r ...
- ICPC — International Collegiate Programming Contest Asia Regional Contest, Yokohama, 2018–12–09 题解
目录 注意!!此题解存在大量假算法,请各位巨佬明辨! Problem A Digits Are Not Just Characters 题面 题意 思路 代码 Problem B Arithmetic ...
- 计蒜客 The 2018 ACM-ICPC Chinese Collegiate Programming Contest Rolling The Polygon
include <iostream> #include <cstdio> #include <cstring> #include <string> #i ...
- The 2018 ACM-ICPC Chinese Collegiate Programming Contest Fight Against Monsters
#include <iostream> #include <cstdio> #include <cstring> #include <string> # ...
- The 2018 ACM-ICPC Chinese Collegiate Programming Contest Caesar Cipher
#include <iostream> #include <cstdio> #include <cstring> #include <string> # ...
- The 2018 ACM-ICPC Chinese Collegiate Programming Contest Maximum Element In A Stack
//利用二维数组模拟 #include <iostream> #include <cstdio> #include <cstring> #include <s ...
- ACM International Collegiate Programming Contest, Tishreen Collegiate Programming Contest (2018) Syria, Lattakia, Tishreen University, April, 30, 2018
ACM International Collegiate Programming Contest, Tishreen Collegiate Programming Contest (2018) Syr ...
随机推荐
- jquery的$().each和$.each的区别
在jquery中,遍历对象和数组,经常会用到$().each和$.each(),两个方法.两个方法是有区别的,从而这两个方法在针对不同的操作上,显示了各自的特点. $().each,对于这个方法,在d ...
- [USACO15OPEN]回文的路径Palindromic Paths
[USACO15OPEN]回文的路径Palindromic Paths 题目描述 Farmer John's farm is in the shape of an N \times NN×N grid ...
- C#/.net基础知识
1 .NET 中类和结构的区别? 答:结构和类具有大体的语法,但是结构受到的限制比类要多.结构不能申明有默认的构造函数,为结构的副本是又编译器创建 和销毁的,所以不需要默认的构造函数和析构函数.结构 ...
- fleet-运行一个全局的单元
运行一个全局的单元 正如前面所提到的,全局单元是有用的,用于在您的集群中的所有机器上运行一个单元.它不会比一个普通的单元差太多,而是一个新的x-fleet参数称为Global=true.这是一个示例单 ...
- Redis hash(哈希)
Redis hash可储存多个键值对,适合储存对象的属性. 1.hset key fieldName fileValue //hset即hash set,set这里是设置的意思.往hash中添加 ...
- Jsp动态生成表格
输入行列: <body> <form action="Train2ResultJsp.jsp"> row:<input type="text ...
- 浅窥ArcGIS Data Store之两斑
关于 ArcGIS Data Store,我们备受大家喜爱的suwenjiang朋友在其博客空间suwenjiang的烂笔头中贡献了<ArcGIS Data Store初体验>一文,全面讲 ...
- 【装载】删除Oracle11G
卸载Oracle步骤:1.停止所有与ORACLE相关的服务.2. 使用OUI(Oracle Universal Installer)卸载Oracle软件. “开始”->“程序”->“O ...
- django之基于cookie和装饰器实现用户认证
示例1 # Create your views here. user = "a" pwd = "a" def login(request): if reques ...
- 宿主机Windows访问虚拟机Linux文件(一)
如果用户使用windows操作系统,但是在虚拟机下配置Linux内核操作操作系统,往往需要实现通过宿主机Windows操作系统访问Linux内核操作系统中资源.本次实验实现的是宿主机windows 1 ...