https://oj.leetcode.com/problems/combination-sum/

给一列数,3 2 1 3 3 8 7 9 ,每个数可以重复多次,给target 7, 问可以加起来得7的所有组合。

递归,类似深搜的思想。

class Solution {
public:
vector<vector<int> > combinationSum(vector<int> &candidates, int target) {
vector<vector<int> > ans;
if(candidates.size()==)
return ans; //remove duplicates
sort(candidates.begin(),candidates.end());
vector<int>::iterator itr = unique(candidates.begin(),candidates.end());
candidates.resize(itr - candidates.begin());
if(candidates[]>target)
return ans; //remove the elements great than target
int len = candidates.size();
while(len>= && candidates[len-] > target)
len--;
candidates.resize(len); vector<int> ansPiece;
combinationSum(candidates,ans,target,,ansPiece); return ans;
}
void combinationSum(vector<int> & candidates,vector<vector<int> > &ans,int target,int pivot,vector<int> ansPiece)
{
if(target == )
{
ans.push_back(ansPiece);
return;
}
if( target < ||pivot == candidates.size())
return; int i = ;
while(target - i>=)
{
if(i != )
ansPiece.push_back(candidates[pivot]);
combinationSum(candidates,ans,target - i,pivot+,ansPiece); i = i + candidates[pivot];
}
}
};

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