【leetcode】1295. Find Numbers with Even Number of Digits

题目如下：

Given an array nums of integers, return how many of them contain an even number of digits.

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 contains an even number of digits.

Constraints:

• 1 <= nums.length <= 500
• 1 <= nums[i] <= 10^5

解题思路：送分题。

代码如下：

class Solution(object):
    def findNumbers(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        res = 0
        for i in nums:
            if len(str(i)) % 2 == 0:
                res += 1
        return res