B. Coupons and Discounts
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

The programming competition season has already started and it's time to train for ICPC. Sereja coaches his teams for a number of year and he knows that to get ready for the training session it's not enough to prepare only problems and editorial. As the training sessions lasts for several hours, teams become hungry. Thus, Sereja orders a number of pizzas so they can eat right after the end of the competition.

Teams plan to train for n times during n consecutive days. During the training session Sereja orders exactly one pizza for each team that is present this day. He already knows that there will be ai teams on the i-th day.

There are two types of discounts in Sereja's favourite pizzeria. The first discount works if one buys two pizzas at one day, while the second is a coupon that allows to buy one pizza during two consecutive days (two pizzas in total).

As Sereja orders really a lot of pizza at this place, he is the golden client and can use the unlimited number of discounts and coupons of any type at any days.

Sereja wants to order exactly ai pizzas on the i-th day while using only discounts and coupons. Note, that he will never buy more pizzas than he need for this particular day. Help him determine, whether he can buy the proper amount of pizzas each day if he is allowed to use only coupons and discounts. Note, that it's also prohibited to have any active coupons after the end of the day n.

Input

The first line of input contains a single integer n (1 ≤ n ≤ 200 000) — the number of training sessions.

The second line contains n integers a1, a2, ..., an (0 ≤ ai ≤ 10 000) — the number of teams that will be present on each of the days.

Output

If there is a way to order pizzas using only coupons and discounts and do not buy any extra pizzas on any of the days, then print "YES" (without quotes) in the only line of output. Otherwise, print "NO" (without quotes).

Examples
Input
4
1 2 1 2
Output
YES
Input
3
1 0 1
Output
NO
Note

In the first sample, Sereja can use one coupon to buy one pizza on the first and the second days, one coupon to buy pizza on the second and the third days and one discount to buy pizzas on the fourth days. This is the only way to order pizzas for this sample.

In the second sample, Sereja can't use neither the coupon nor the discount without ordering an extra pizza. Note, that it's possible that there will be no teams attending the training sessions on some days.

/*
ACM训练队要训练n天,第i天有ai个队训练,每个队伍需要一张披萨,教练去买披萨。有两种优惠券第一种是一次买两张,另一种是第一天买一张,
第二天必须买一张。优惠券无限多,问教练能不能用优惠券买全部的披萨,每天买的披萨不会超过需求,且优惠券不能浪费。 贪心:贪心的原则就是尽量不使第二天的数量受影响,就是第一天的能用没两张披萨的优惠圈就用这个,实在不行才用买一张的。
*/
#include<iostream>
#include<string.h>
#include<string>
#include<algorithm>
#include<stdio.h>
#include<vector>
#include<map>
#include<set>
#define N 200010
using namespace std;
int main()
{
//freopen("C:\\Users\\acer\\Desktop\\in.txt","r",stdin);
int n,a[N];
scanf("%d",&n);
for(int i=;i<=n;i++)
{
scanf("%d",&a[i]);
}
int f=;
for(int i=;i<n;i++)
{
if(a[i]%)//奇数个
{
if(!a[i+])
{
f=;
break;
}
a[i+]--;
}
}
if(f)
{
puts("NO");
return ;
}
if(a[n]%==)
puts("YES");
else
puts("NO");
return ;
}

Codeforces 376B. Coupons and Discounts的更多相关文章

  1. Codeforces 731B Coupons and Discounts(贪心)

    题目链接 Coupons and Discounts 逐步贪心即可. 若当前位为奇数则当前位的下一位减一,否则不动. #include <bits/stdc++.h> using name ...

  2. CodeForces 731B Coupons and Discounts (水题模拟)

    题意:有n个队参加CCPC,然后有两种优惠方式,一种是一天买再次,一种是买两天,现在让你判断能不能找到一种方式,使得优惠不剩余. 析:直接模拟,如果本次是奇数,那么就得用第二种,作一个标记,再去计算下 ...

  3. 【50.49%】【codeforces 731B】Coupons and Discounts

    time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...

  4. Coupons and Discounts

    Coupons and Discounts time limit per test 1 second memory limit per test 256 megabytes input standar ...

  5. 【Codeforces】Round #376 (Div. 2)

    http://codeforces.com/contest/731 不发题面了,自己点链接 总结一下 考场上 原以为这次要加很多raiting... 但FST狗记邓,只加了58rating 总结一下 ...

  6. Codeforces Round #376 (Div. 2) A B C 水 模拟 并查集

    A. Night at the Museum time limit per test 1 second memory limit per test 256 megabytes input standa ...

  7. 【codeforces 754D】Fedor and coupons

    time limit per test4 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...

  8. codeforces 754D. Fedor and coupons

    D. Fedor and coupons time limit per test 4 seconds memory limit per test 256 megabytes input standar ...

  9. Codeforces 161 B. Discounts (贪心)

    题目链接:http://codeforces.com/contest/161/problem/B 题意: 有n个商品和k辆购物车,给出每个商品的价钱c和类别t(1表示凳子,2表示铅笔),如果一辆购物车 ...

随机推荐

  1. 【转载】关于api-ms-win-crt-runtimel1-1-0.dll缺失的解决方案

    关于api-ms-win-crt-runtimel1-1-0.dll缺失的解决方案 目录 关于api-ms-win-crt-runtimel1-1-0dll缺失的解决方案 目录 安装VC redite ...

  2. Tomcat的四种基于HTTP协议的Connector性能比较

    Tomcat从5.5版本开始,支持以下四种Connector的配置分别为: <Connector port="8081" protocol="org.apache. ...

  3. Linux入门之常用命令(10)软连接 硬链接

    在Linux系统中,内核为每一个新创建的文件分配一个Inode(索引结点),每个文件都有一个惟一的inode号.文件属性保存在索引结点里,在访问文件时,索引结点被复制到内存在,从而实现文件的快速访问. ...

  4. BGP协议

    BGP属于自治系统间路由协议.BGP的主要目标是为处于不同AS中的路由器之间进行路由信息通信提供保障.BGP既不是纯粹的矢量距离协议,也不是纯粹的链路状态协议,通常被称为通路向量路由协议.这是因为BG ...

  5. 18.Llinux-触摸屏驱动(详解)

    本节的触摸屏驱动也是使用之前的输入子系统 1.先来回忆之前第12节分析的输入子系统 其中输入子系统层次如下图所示, 其中事件处理层的函数都是通过input_register_handler()函数注册 ...

  6. Power Strings poj2406(神代码)

    Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 29402   Accepted: 12296 D ...

  7. 使用Scrapy创建一个爬虫

    使用Scrapy创建一个爬虫 创建项目 您可以使用下面的命令来创建 Scrapy 项目: scrapy startproject 项目名称 例:scrapy startproject scrapy_p ...

  8. 第9期Unity User Group Beijing图文报道:《Unity实战经验分享》

    时间来到了金秋九月,北京UUG活动也来到了第九期.本次活动的主题为<Unity实战经验分享>,为此我们邀请了3位资深的行业大神.这次我们仍然在北京市海淀区丹棱街5号微软大厦举行活动,在这里 ...

  9. C#泛型基础知识点总结

    1.0  什么是泛型 泛型是C#2.0和CLR(公共语言运行时)升级的一个新特性,泛型为.NET 框架引入了一个叫 type parameters(类型参数)的概念,type parameters 使 ...

  10. ASP.NET MVC AJAX的调用示例

    @{ ViewBag.Title = "Home Page"; //下面引用Jquery和unobtrusive-ajax } @Scripts.Render("~/bu ...