【Leetcode】92. Reverse Linked List II && 206. Reverse Linked List

　　The task is reversing a list in range m to n(92) or a whole list(206).

　　All in one : U need three pointers to achieve this goal.

　　　1) Pointer to last value

　　　2) Pointer to cur p value

　　　3) Pointer to next value

　　Here, showing my code wishes can help u.

　　Of course, you also need to record four nodes in special postions.

　　　1) newM　　2)newN　　3)beforeM　　4)afterN

　　These may be some complex(stupid) but it's really friend to people who are reading my code and easily understood.

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;

typedef struct ListNode {
    int val;
    ListNode *next;
    ListNode(int x) : val(x), next(NULL) {}
}ListNode, *PNode;

void create_List(PNode head)
{
    PNode  p = head;
    int n;
    cin>>n;
    for(int i = ; i < n ;i ++){
        int t;
        cin>>t;
        if(i == ){
            head -> val = t;
            head -> next = NULL;
            cout<<"head is "<<head->val<<endl;
            p = head;
        }else{
            PNode newNode = (PNode) malloc(sizeof(PNode));
            newNode -> val = t;
            newNode -> next = NULL;
            p -> next = newNode;
            p = newNode;
            cout<<"p is "<<p -> val<<endl;
        }
    }
}

void display(PNode  head)
{
    PNode p = head;
    while(p){
        cout<<p->val<<" -> ";
        p = p -> next;
    }cout<<endl;
}

class Solution {
public:
    ListNode* reverseBetween(ListNode* head, int m, int n) {
        if(m == n || head == NULL) return head;
        ListNode *pLast = head, *p = head -> next, *pNext = NULL;
        ListNode *newN = NULL, *newM = NULL, *beforeM = head, *afterN = NULL;
        int pos = ;
        while(p){
            if(pos == m - ){
                beforeM = pLast;
                pLast = p;
                p = p -> next;
            }
            else if(pos >= m && pos < n){
                pNext = p -> next;
                p -> next = pLast;
                if(pos == m){
                    pLast -> next = NULL;
                    newM = pLast;
                }
                pLast = p;
                if(pos == n - ){
                    newN = p;
                    afterN = pNext;
                }
                p = pNext;
            }else{
                pLast = p;
                p = p -> next;
            }
            pos ++;
        }
        if( m== && afterN == NULL){
            head = newN;
        }else if(m == ){
            head = newN;
            newM -> next = afterN;
        }else{
            beforeM -> next = newN;
            newM -> next = afterN;
        }
        return head;
    }

    ListNode* reverseList(ListNode* head) {
        if(head == NULL) return head;
        ListNode *pLast = head, *p = head -> next, *pNext = NULL;
        while(p){
            pNext = p -> next;
            p -> next = pLast;
            if(pLast == head){
                pLast -> next = NULL;
            }
            pLast = p;
            p = pNext;
        }
        head = pLast;
        return head;
    }
};
int main()
{
    PNode head = (PNode) malloc(sizeof(PNode));;
    create_List(head);
    cout<<"after creating , head is "<<head->val<<endl;
    display(head);
    Solution tmp = Solution();
    //tmp.reverseBetween(head, 2, 3);
    tmp.reverseList(head);
    system("pause");
    return ;
}