链表的实现 -- 数据结构与算法的javascript描述 第六章

链表

链表是由一组节点组成的集合。每个节点都使用一个对象的引用指向它的后继。指向另一个节点的引用叫做链

结构示意图 ：

链表头需要我们标识 head

 { element:head,next:obj1 }   ==>   { element:obj1,next:obj2 }   ==>   { element:obj2,next:obj3 }   ==>   { element:obj3,next:null }  ==>   null 

head 是我们内部标识，我们默认不显示给用户这个数据，只用于内部使用。 即用户的链表数据中 不会有head

/**
     * 节点
     * @constructor
     */
    function Node(element){
        this.element = element,
        this.next = null;
    }

    /**
     * 链表
     * @constructor
     */
    function LinkedList(){
        var me = this ;
        me.head = new Node('head')
        me.find = find;
        me.insert = insert;
        me.remove = remove;
        me.display = display;
        //查找元素
        function find(element){
            var cur = me.head;
            while(cur.element!=element){
                cur = cur.next;
            }
            return cur;
        }
        //插入元素到链表
        function insert(newElement,item){
            var current ;
            if(me.head.next==null && !item){
                current = me.head;
            }else if(item){
                current = me.find(item);
            }else {
                throw Error("need item")
            }
            var newNode = new Node(newElement);

            newNode.next = current.next;
            current.next = newNode;
        }
        //从链表中移除元素
        function remove(element){
            var curPrev = findPrev(element);
            var curNext = find(element).next;
            curPrev.next = curNext;
        }
        //查找前一个元素
        function findPrev(element){
            var cur = me.head;
            while(!(cur.next==null) && cur.next.element!=element){
               cur = cur.next;
            }
            return cur;
        }
        //打印所有链表元素
        function display(){
            var s = '',cur = me.head;
            while(!(cur.next==null)){
                s += cur.next.element +"  ";
                cur = cur.next;
            }
            console.log(s)
        }

    }

测试

 //链表测试
        var cities = new LinkedList();
        cities.insert("Conway");
        cities.insert("Russellville", "Conway");
        cities.insert("Carlisle", "Russellville");
        cities.insert("Alma", "Carlisle");
        cities.display();   // Conway  Russellville  Carlisle  Alma
        cities.remove("Carlisle");
        cities.display();  // Conway  Russellville  Alma