剑指offer-面试题66-构建乘积数组-发散思维

/*
题目：
    链接：https://www.nowcoder.com/questionTerminal/94a4d381a68b47b7a8bed86f2975db46
	来源：牛客网
 
	给定一个数组A[0,1,...,n-1],请构建一个数组B[0,1,...,n-1],
	其中B中的元素B[i]=A[0]*A[1]*...*A[i-1]*A[i+1]*...*A[n-1]。不能使用除法。
思路：
    C[i] = A[0]*...*A[i-1];
	D[i] = A[i+1]*...*A[n-1];
	B[i] = C[i]*D[i];
**/
#include<iostream>
#include<cstring>
#include<vector>
#include<algorithm>
#include<map>
 
using namespace std;
 
vector<int> multiply(const vector<int>& A) {
    vector<int> B;
    int length = A.size();
    B.push_back(1);
    for(int i = 1; i < length; i++){
        B.push_back(B.back()*A[i-1]);
    }
 
    int temp = 1;
    for(int i = length-2; i >= 0; i--){
        temp *= A[i+1];
        B[i] *= temp;
    }
    return B;
 
}
int main(){
   vector<int> A={1,2,3,4,5};
   vector<int> B=multiply(A);
   for(int i = 0; i < B.size(); i++){
        cout<<B[i]<<" ";
   }
}