编程算法 - 字符串的排列 代码(C)

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https://blog.csdn.net/u012515223/article/details/35593485

字符串的排列 代码(C)

本文地址: http://blog.csdn.net/caroline_wendy

题目: 输入一个字符串, 打印出该字符串中字符的全部排列.

方法: 使用递归依次交换位置, 打印输出.

代码:

/*
 * main.cpp
 *
 *  Created on: 2014.6.12
 *      Author: Spike
 */

/*eclipse cdt, gcc 4.8.1*/

#include <stdio.h>

void Permutation(char* str, char* begin);

void Permutation(char* str){
    if(str == NULL)
        return;
    Permutation(str, str);
}

void Permutation(char* str, char* begin) {
    if(*begin == '\0') {
        printf("%s\n", str);
        return;
    }

	for (char* c = begin; *c != '\0'; ++c) {
		char temp = *c;
		*c = *begin;
		*begin = temp;

		Permutation(str, begin + 1);

		temp = *c;
		*c = *begin;
		*begin = temp;
	}

}

void Test(char* pStr)
{
    if(pStr == NULL)
        printf("Test for NULL begins:\n");
    else
        printf("Test for %s begins:\n", pStr);

    Permutation(pStr);

    printf("\n");
}

int main(void)
{
    char str[] = "abc";
    Test(str);

    return 0;
}

输出:

Test for abc begins:
abc
acb
bac
bca
cba
cab