B. Pasha and Tea

Time Limit: 20 Sec

Memory Limit: 256 MB

题目连接

http://codeforces.com/contest/557/problem/B

Description

Pasha decided to invite his friends to a tea party. For that occasion, he has a large teapot with the capacity of w milliliters and 2n tea cups, each cup is for one of Pasha's friends. The i-th cup can hold at most ai milliliters of water.

It turned out that among Pasha's friends there are exactly n boys and exactly n girls and all of them are going to come to the tea party. To please everyone, Pasha decided to pour the water for the tea as follows:

Pasha can boil the teapot exactly once by pouring there at most w milliliters of water;
    Pasha pours the same amount of water to each girl;
    Pasha pours the same amount of water to each boy;
    if each girl gets x milliliters of water, then each boy gets 2x milliliters of water.

In the other words, each boy should get two times more water than each girl does.

Pasha is very kind and polite, so he wants to maximize the total amount of the water that he pours to his friends. Your task is to help him and determine the optimum distribution of cups between Pasha's friends.

Input

The first line of the input contains two integers, n and w (1 ≤ n ≤ 105, 1 ≤ w ≤ 109) — the number of Pasha's friends that are boys (equal to the number of Pasha's friends that are girls) and the capacity of Pasha's teapot in milliliters.

The second line of the input contains the sequence of integers ai (1 ≤ ai ≤ 109, 1 ≤ i ≤ 2n) — the capacities of Pasha's tea cups in milliliters.

Output

IPrint a single real number — the maximum total amount of water in milliliters that Pasha can pour to his friends without violating the given conditions. Your answer will be considered correct if its absolute or relative error doesn't exceed 10 - 6.

Sample Input

2 4
1 1 1 1

Sample Output

3

HINT

题意

给你n个女人和n个男人和w升茶

有2个操作

给所有男人倒同样大小的茶

给所有女人倒同样大小的茶

要求满足男人的茶至少是女人的2倍

问 最多倒多少茶?

题解:

排序贪心一下

具体看代码吧,很短,应该很好理解

代码

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
#include <map>
#include <stack>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define test freopen("test.txt","r",stdin)
#define maxn 300005
#define mod 10007
#define eps 1e-9
const int inf=0x3f3f3f3f;
const ll infll = 0x3f3f3f3f3f3f3f3fLL;
inline ll read()
{
ll x=,f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
//************************************************************************************** double a[maxn];
int main()
{
int n=read(),w=read();
for(int i=;i<*n;i++)
scanf("%lf",&a[i]);
sort(a,a+*n);
double mi=a[],ma=a[n];
double ans=min(mi,ma/);
ans=ans**n;
ans=min(ans,w*1.0);
printf("%.7f\n",ans);
}

Codeforces Round #311 (Div. 2)B. Pasha and Tea 水题的更多相关文章

  1. Codeforces Round #311 (Div. 2)B. Pasha and Tea二分

    B. Pasha and Tea time limit per test 1 second memory limit per test 256 megabytes input standard inp ...

  2. Codeforces Round #337 (Div. 2) A. Pasha and Stick 水题

    A. Pasha and Stick   Pasha has a wooden stick of some positive integer length n. He wants to perform ...

  3. Codeforces Round #311 (Div. 2) A. Ilya and Diplomas 水题

    A. Ilya and Diplomas Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/557/ ...

  4. Codeforces Round #297 (Div. 2)A. Vitaliy and Pie 水题

    Codeforces Round #297 (Div. 2)A. Vitaliy and Pie Time Limit: 2 Sec  Memory Limit: 256 MBSubmit: xxx  ...

  5. Codeforces Round #290 (Div. 2) A. Fox And Snake 水题

    A. Fox And Snake 题目连接: http://codeforces.com/contest/510/problem/A Description Fox Ciel starts to le ...

  6. Codeforces Round #322 (Div. 2) A. Vasya the Hipster 水题

    A. Vasya the Hipster Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/581/p ...

  7. Codeforces Round #373 (Div. 2) B. Anatoly and Cockroaches 水题

    B. Anatoly and Cockroaches 题目连接: http://codeforces.com/contest/719/problem/B Description Anatoly liv ...

  8. Codeforces Round #368 (Div. 2) A. Brain's Photos 水题

    A. Brain's Photos 题目连接: http://www.codeforces.com/contest/707/problem/A Description Small, but very ...

  9. Codeforces Round #359 (Div. 2) A. Free Ice Cream 水题

    A. Free Ice Cream 题目连接: http://www.codeforces.com/contest/686/problem/A Description After their adve ...

随机推荐

  1. 【C++】非原创|统计代码覆盖率(一:C++)

    也是转别人的,因为我c++好菜好菜啊... http://blog.chinaunix.net/uid-23741326-id-3316943.html c++跟C基本是一样的,统计覆盖率,需要生成g ...

  2. LR之性能分析基础

    1.判断测试结果有效性 2.分析要点提示 3.Analysis主要提供的6大类分析图 4.分析流程

  3. LR 解决中文乱码(来源——百度)

    因为我们使用的中文操作系统默认的中文编码格式是GB2312,所以LR对服务器的返回内容自动使用GB2312方式阅读的,但是几乎所有的中文网站现在都在使用UTF-8的方式来编码,由于解码编码的方式不同最 ...

  4. “iOS 推送通知”详解:从创建到设置到运行

    这是一篇编译的文章,内容均出自Parse.com的iOS开发教程,同时作者还提供了视频讲解.本文将带领开发者一步一步向着iOS推送通知的深处探寻,掌握如何配置iOS推送通知的奥义. 介绍一点点背景资料 ...

  5. Java多线程的五种状态

    新建状态:new Thread(参数)之后,建立了一个线程对象; 就绪状态:线程对象建立之后,调用start()方法,进入就绪状态,此时并不会直接调用run()方法,线程进入运行状态还需要抢占CPU资 ...

  6. 用js完成blog项目

    //前台调用 var $ = function (args) { return new Base(args); } //基础库 function Base(args) { //创建一个数组,来保存获取 ...

  7. 转-sketch技巧

    10个帮你UI设计提速的Sketch使用技巧 2015-4-11 09:59| 发布者: yuanxingbbs| 查看: 1129| 评论: 0   选择使用Sketch的理由很多,因为好奇跟风安装 ...

  8. Linux-head,tail用法

    linux ---tail命令 linux中tail命令---用于查看文件内容 最基本的是cat.more和less. 1. 如果你只想看文件的前5行,可以使用head命令,如: head -5 /e ...

  9. jsp界面项目绝对路径问题

    方法一:直接采用绝对路径 (不推荐) 在JSP页面端,获得本项目的绝对地址(如果你的项目叫MyApp,那么获得到的地址就是 http://localhost:8080/MyApp/): 代码如下: & ...

  10. spring properties resolve 问题

    在stackoverflow上看到一个问题 配置如下: <context:property-placeholder location="/WEB-INF/application-cus ...