2063. Black and White

Time limit: 1.0 second
Memory limit: 64 MB
Let’s play a game. You are given a row of n balls, each ball is either black or white. Their positions in a row are numbered from 1 to n. You know the total number of balls n, but have no information about the order of their colors. You don’t even know how many white balls are there.
You are allowed to make queries v u (1 ≤ vu ≤ n). If the ball on position v is black and the ball on position u is white, then these two balls are swapped. Otherwise, nothing happens. Even if the balls are swapped, you don’t get any feedback.
After a number of queries (can be zero) you a required to make a "statement." "Statement" also consists of two positions vu. Your goal is to choose positions, that contain two balls of the same color.
In this problem we ask you to print both queries and a "statement", that comes after them.
A single test can contain several games. Furthermore, all tests except the first one contain 99 game descriptions. In the first game n = 2, in the second — n = 3 ... in the last game n = 100.
First test is the same as the sample below.
In all other tests your program must make the right statement at least in 80 games.
Note, that we do not guarantee that the tests are random.

Input

First line contains m — number of games in the test. For every test, except for the first one,m=99.
Remaining lines contain ciphered (except for the first test) order of balls in the row. Thus we guarantee, that the tests are determined beforehand and do not depend on your strategy. Please, do not try to use this data in any way and do not try to decipher it.

Output

Output m game descriptions.
One description consists of (k+1) lines, where k — number of queries made by your program.
First k lines should contain the queries in the following format: ? v u (1 ≤ vu ≤ nv ≠ u).
The last line should contain the "statement": ! v u (1 ≤ vu ≤ nv ≠ u).
Total amount of lines (over all games in a test) should not exceed 5 · 105.

Sample

input output
2
01
101
? 1 2
? 2 1
? 1 2
! 2 1
? 1 2
? 3 1
! 1 2

Notes

In the sample test white balls are marked as 0, black ones — as 1. Let’s examine the sample closely.
First game: 01 → 01 → 10 → 01 — we did not guess correctly.
Second game: 101 → 011 → 110 — we guessed correctly.
In this test we have guessed correctly in one game out of two.
Problem Author: Alexey Danilyuk
Problem Source: Ural Regional School Programming Contest 2015
Difficulty: 421
 
题意:有n个球,要么0,要么1,你先进行若干次操作,选择u,v,如果a[u]<a[v],那么他们交换
以上操作无任何反馈
最后进行一个论断:你选择两个你认为相等的位置输出
正确80%以上即可。
 
分析:首先我们可以都过交换操作来个冒泡之类的排序
然后随机选择两个相邻的点,正确率为(n-2)/(n-1)
总的正确率80%应该没问题。
 
 #include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std; int n; int main()
{
ios::sync_with_stdio();
srand(time());
int m;
cin >> m;
for(int n = ; n <= m + ; n++)
{
for(int i = ; i <= n; i++)
for(int j = ; j < i; j++)
cout << "? " << j << ' ' << i << "\n";
int x = rand() % (n - ) + ;
cout << "! " << x << ' ' << x + << "\n";
cout.flush();
}
return ;
}

ural 2063. Black and White的更多相关文章

  1. ural 1243. Divorce of the Seven Dwarfs

    1243. Divorce of the Seven Dwarfs Time limit: 1.0 secondMemory limit: 64 MB After the Snow White wit ...

  2. ural 1221. Malevich Strikes Back!

    1221. Malevich Strikes Back! Time limit: 1.0 secondMemory limit: 64 MB After the greatest success of ...

  3. URAL 1297 Palindrome 后缀数组

    D - Palindrome Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Subm ...

  4. URAL 1297 最长回文子串(后缀数组)

    1297. Palindrome Time limit: 1.0 secondMemory limit: 64 MB The “U.S. Robots” HQ has just received a ...

  5. URAL - 1243 - Divorce of the Seven Dwarfs (大数取模)

    1243. Divorce of the Seven Dwarfs Time limit: 1.0 second Memory limit: 64 MB After the Snow White wi ...

  6. Ural 1225. Flags 斐波那契DP

    1225. Flags Time limit: 1.0 secondMemory limit: 64 MB On the Day of the Flag of Russia a shop-owner ...

  7. imshow() displays a white image for a grey image

    Matlab expects images of type double to be in the 0..1 range and images that are uint8 in the 0..255 ...

  8. 后缀数组 POJ 3974 Palindrome && URAL 1297 Palindrome

    题目链接 题意:求给定的字符串的最长回文子串 分析:做法是构造一个新的字符串是原字符串+反转后的原字符串(这样方便求两边回文的后缀的最长前缀),即newS = S + '$' + revS,枚举回文串 ...

  9. ural 2071. Juice Cocktails

    2071. Juice Cocktails Time limit: 1.0 secondMemory limit: 64 MB Once n Denchiks come to the bar and ...

随机推荐

  1. C语言中一个替换 strcpy的极好的方法

    在C语言中有个方法:strcpy() 使用时经常容易内存申请不足,或是没有申请内存导致,复制的时候报错,我新写了一个方法,弥补这个缺陷 char *strcpy1(char *strDes, char ...

  2. NYOJ之奇偶数分离

    aaarticlea/png;base64,iVBORw0KGgoAAAANSUhEUgAAAscAAAJ8CAIAAACdmZvPAAAgAElEQVR4nO3dPVLjStsG4G8T5CyEFC

  3. Javascript和Java获取各种form表单信息的简单实例

    大家都知道我们在提交form的时候用了多种input表单.可是不是每一种input表单都是很简单的用Document.getElementById的方式就可以获取到的.有一些组合的form类似于che ...

  4. I2C学习

    详细的解释: 读写状态机图

  5. 基于spring4.0配置分布式ehcache,以及相关使用

    说明:本文是基于RMI手动同步的方式,使用程序动态注入配置缓存,抛弃传统的ehcache.xml配置方式 1,注入cacheManager管理所有缓存,添加各个缓存名及相关参数配置: 思路大致是: 在 ...

  6. java web开发环境配置

    一:安装jdk   http://www.java.com/zh_TW/ 二:下载tomcat,这里是zip版.http://tomcat.apache.org/download-70.cgi 三:在 ...

  7. PHP中array_merge和array相加的区别分析

    今天处理一个这样的问题:如何获取字符键名相同值不同的两个数组值集合,用array_merge和数组相加都不可行,让我认真比较了下PHP中array_merge和array相加的区别 首先来看看键名是s ...

  8. C# 中的Singleton模式

    一般写Singleton基本都是一下这个套路 class Singleton { public static Singleton instance; private Singleton() { } p ...

  9. Qt Designer 修改窗体大小改变控件位置

    一.新建一个窗体 用qt designer 新建一个QWidget窗体, 在窗体中右键 选择布局, 发现布局是选择不了的,这个是因为窗体里面没有添加控件, 任意添加空间后便可选择 右键-- 布局-- ...

  10. 【译】Visual Studio 15 预览版更新说明

    序:恰逢Build2016大会召开,微软发布了VS2015的update2更新包和VS2016预览版.本人正在提升英文水平中,于是在这里对VS2016预览版的官方文档进行了部分翻译.因为VS有些功能使 ...