2063. Black and White

Time limit: 1.0 second
Memory limit: 64 MB
Let’s play a game. You are given a row of n balls, each ball is either black or white. Their positions in a row are numbered from 1 to n. You know the total number of balls n, but have no information about the order of their colors. You don’t even know how many white balls are there.
You are allowed to make queries v u (1 ≤ vu ≤ n). If the ball on position v is black and the ball on position u is white, then these two balls are swapped. Otherwise, nothing happens. Even if the balls are swapped, you don’t get any feedback.
After a number of queries (can be zero) you a required to make a "statement." "Statement" also consists of two positions vu. Your goal is to choose positions, that contain two balls of the same color.
In this problem we ask you to print both queries and a "statement", that comes after them.
A single test can contain several games. Furthermore, all tests except the first one contain 99 game descriptions. In the first game n = 2, in the second — n = 3 ... in the last game n = 100.
First test is the same as the sample below.
In all other tests your program must make the right statement at least in 80 games.
Note, that we do not guarantee that the tests are random.

Input

First line contains m — number of games in the test. For every test, except for the first one,m=99.
Remaining lines contain ciphered (except for the first test) order of balls in the row. Thus we guarantee, that the tests are determined beforehand and do not depend on your strategy. Please, do not try to use this data in any way and do not try to decipher it.

Output

Output m game descriptions.
One description consists of (k+1) lines, where k — number of queries made by your program.
First k lines should contain the queries in the following format: ? v u (1 ≤ vu ≤ nv ≠ u).
The last line should contain the "statement": ! v u (1 ≤ vu ≤ nv ≠ u).
Total amount of lines (over all games in a test) should not exceed 5 · 105.

Sample

input output
2
01
101
? 1 2
? 2 1
? 1 2
! 2 1
? 1 2
? 3 1
! 1 2

Notes

In the sample test white balls are marked as 0, black ones — as 1. Let’s examine the sample closely.
First game: 01 → 01 → 10 → 01 — we did not guess correctly.
Second game: 101 → 011 → 110 — we guessed correctly.
In this test we have guessed correctly in one game out of two.
Problem Author: Alexey Danilyuk
Problem Source: Ural Regional School Programming Contest 2015
Difficulty: 421
 
题意:有n个球,要么0,要么1,你先进行若干次操作,选择u,v,如果a[u]<a[v],那么他们交换
以上操作无任何反馈
最后进行一个论断:你选择两个你认为相等的位置输出
正确80%以上即可。
 
分析:首先我们可以都过交换操作来个冒泡之类的排序
然后随机选择两个相邻的点,正确率为(n-2)/(n-1)
总的正确率80%应该没问题。
 
 #include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std; int n; int main()
{
ios::sync_with_stdio();
srand(time());
int m;
cin >> m;
for(int n = ; n <= m + ; n++)
{
for(int i = ; i <= n; i++)
for(int j = ; j < i; j++)
cout << "? " << j << ' ' << i << "\n";
int x = rand() % (n - ) + ;
cout << "! " << x << ' ' << x + << "\n";
cout.flush();
}
return ;
}

ural 2063. Black and White的更多相关文章

  1. ural 1243. Divorce of the Seven Dwarfs

    1243. Divorce of the Seven Dwarfs Time limit: 1.0 secondMemory limit: 64 MB After the Snow White wit ...

  2. ural 1221. Malevich Strikes Back!

    1221. Malevich Strikes Back! Time limit: 1.0 secondMemory limit: 64 MB After the greatest success of ...

  3. URAL 1297 Palindrome 后缀数组

    D - Palindrome Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Subm ...

  4. URAL 1297 最长回文子串(后缀数组)

    1297. Palindrome Time limit: 1.0 secondMemory limit: 64 MB The “U.S. Robots” HQ has just received a ...

  5. URAL - 1243 - Divorce of the Seven Dwarfs (大数取模)

    1243. Divorce of the Seven Dwarfs Time limit: 1.0 second Memory limit: 64 MB After the Snow White wi ...

  6. Ural 1225. Flags 斐波那契DP

    1225. Flags Time limit: 1.0 secondMemory limit: 64 MB On the Day of the Flag of Russia a shop-owner ...

  7. imshow() displays a white image for a grey image

    Matlab expects images of type double to be in the 0..1 range and images that are uint8 in the 0..255 ...

  8. 后缀数组 POJ 3974 Palindrome && URAL 1297 Palindrome

    题目链接 题意:求给定的字符串的最长回文子串 分析:做法是构造一个新的字符串是原字符串+反转后的原字符串(这样方便求两边回文的后缀的最长前缀),即newS = S + '$' + revS,枚举回文串 ...

  9. ural 2071. Juice Cocktails

    2071. Juice Cocktails Time limit: 1.0 secondMemory limit: 64 MB Once n Denchiks come to the bar and ...

随机推荐

  1. Swift - 状态栏颜色显示(字体、背景)

    ios上状态栏 就是指的最上面的20像素高的部分 状态栏分前后两部分,要分清这两个概念,后面会用到: 前景部分:就是指的显示电池.时间等部分: 背景部分:就是显示黑色或者图片的背景部分: 如下图:前景 ...

  2. Linux安装xwindow图形界面

    在我们安装Linux系统时,刚开始的时候可能没有安装图形界面的需要,但在使用过程中却有可能产生这种需求.那么这种情况下,我们需不需要重新安装Linux系统来安装桌面呢?答案是不需要.下面我将交大家在已 ...

  3. PHP实现执行定时任务的几种思路详解

    转:https://segmentfault.com/a/1190000002955509 PHP本身是没有定时功能的,PHP也不能多线程.PHP的定时任务功能必须通过和其他工具结合才能实现,例如Wo ...

  4. 几年前做家教写的C教程(之二)

    C语言学习宝典(2) 认识C语言中的运算符: (1)算术运算符   (+  -  *  /  %) (2)关系运算符    (>  <  ==  >=  <=  != ) (3 ...

  5. [Tools] Eclipse使用小技巧-持续更新

    [背景] 使用之中发现一些eclipse使用的小技巧,记录下来供以后查阅   Eclipse保存preferences,并导入到其他workspaces The Export wizard can b ...

  6. ASP.NET 5探险(1):Azure中配置连接字符串、独立项目执行EF7数据迁移

    (此文章同时发表在本人微信公众号“dotNET每日精华文章”,欢迎右边二维码来关注.) 题记:我开始把ASP.NET 5用于生产系统开发已经有1个多月了,也填了一些坑积累了一些经验,从今天开始会陆陆续 ...

  7. android倒计时(整理)

    android倒计时 用到CountDownTimer Android中文API(143) —— CountDownTimer 前言 本章内容android.os.CountDownTime章节,版本 ...

  8. 汇编学习(四)——算术运算程序

    (一)跳转指令 一.无条件跳转指令(不管标志寄存器,执行到这句直接跳转) 1.段内直接跳转指令 (1)指令格式: JMP SHORT short_label; IP<--IP+DB,即代码直接跳 ...

  9. Hibernate 和 快照

    Hibernate我们已经学了四天,该讲的知识我们已经讲完,明天放假,后天练习一天就要结束hibernate的学习,有点不舍的,想来hibernate也不是传说中的那么难,在次将hibernate中三 ...

  10. 使用lsof查看进程句柄使用情况

    lsof -n |awk '{print $2}'|sort|uniq -c |sort -nr|more