[LeetCode] Shortest Word Distance II 最短单词距离之二
Design a class which receives a list of words in the constructor, and implements a method that takes two words word1 and word2 and return the shortest distance between these two words in the list. Your method will be called repeatedly many times with different parameters.
Example:
Assume that words = ["practice", "makes", "perfect", "coding", "makes"].
Input: word1 =“coding”, word2 =“practice”
Output: 3
Input: word1 ="makes", word2 ="coding"
Output: 1
Note:
You may assume that word1 does not equal to word2, and word1 and word2 are both in the list.
这道题是之前那道 Shortest Word Distance 的拓展,不同的是这次我们需要多次调用求最短单词距离的函数,那么用之前那道题的解法二和三就非常不高效,而当时摒弃的解法一的思路却可以用到这里,这里用 HashMap 来建立每个单词和其所有出现的位置的映射,然后在找最短单词距离时,只需要取出该单词在 HashMap 中映射的位置数组进行两两比较即可,参见代码如下:
解法一:
class WordDistance {
public:
WordDistance(vector<string>& words) {
for (int i = ; i < words.size(); ++i) {
m[words[i]].push_back(i);
}
}
int shortest(string word1, string word2) {
int res = INT_MAX;
for (int i = ; i < m[word1].size(); ++i) {
for (int j = ; j < m[word2].size(); ++j) {
res = min(res, abs(m[word1][i] - m[word2][j]));
}
}
return res;
}
private:
unordered_map<string, vector<int> > m;
};
我们可以优化上述的代码,使查询的复杂度由上面的 O(MN) 变为 O(M+N),其中M和N为两个单词的长度,需要两个指针i和j来指向位置数组中的某个位置,开始初始化都为0,然后比较位置数组中的数字,将较小的一个的指针向后移动一位,直至其中一个数组遍历完成即可,参见代码如下:
解法二:
class WordDistance {
public:
WordDistance(vector<string>& words) {
for (int i = ; i < words.size(); ++i) {
m[words[i]].push_back(i);
}
}
int shortest(string word1, string word2) {
int i = , j = , res = INT_MAX;
while (i < m[word1].size() && j < m[word2].size()) {
res = min(res, abs(m[word1][i] - m[word2][j]));
m[word1][i] < m[word2][j] ? ++i : ++j;
}
return res;
}
private:
unordered_map<string, vector<int> > m;
};
Github 同步地址:
https://github.com/grandyang/leetcode/issues/244
类似题目:
参考资料:
https://leetcode.com/problems/shortest-word-distance-ii/
https://leetcode.com/problems/shortest-word-distance-ii/discuss/67028/Java-Solution-using-HashMap
https://leetcode.com/problems/shortest-word-distance-ii/discuss/67066/9-line-O(n)-C%2B%2B-Solution
LeetCode All in One 题目讲解汇总(持续更新中...)
[LeetCode] Shortest Word Distance II 最短单词距离之二的更多相关文章
- [LeetCode] 244. Shortest Word Distance II 最短单词距离 II
This is a follow up of Shortest Word Distance. The only difference is now you are given the list of ...
- [LeetCode] Shortest Word Distance III 最短单词距离之三
This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as ...
- [leetcode]244. Shortest Word Distance II最短单词距离(允许连环call)
Design a class which receives a list of words in the constructor, and implements a method that takes ...
- [LeetCode] 245. Shortest Word Distance III 最短单词距离 III
This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as ...
- LeetCode 243. Shortest Word Distance (最短单词距离)$
Given a list of words and two words word1 and word2, return the shortest distance between these two ...
- LeetCode Shortest Word Distance II
原题链接在这里:https://leetcode.com/problems/shortest-word-distance-ii/ 题目: This is a follow up of Shortest ...
- [LeetCode] Shortest Word Distance 最短单词距离
Given a list of words and two words word1 and word2, return the shortest distance between these two ...
- [LeetCode] Shortest Word Distance I & II & III
Shortest Word Distance Given a list of words and two words word1 and word2, return the shortest dist ...
- LeetCode Shortest Word Distance
原题链接在这里:https://leetcode.com/problems/shortest-word-distance/ 题目: Given a list of words and two word ...
随机推荐
- 基于傅里叶变换和PyQt4开发一个简单的频率计数器
小学期的<信号与系统>课,要求写一个频率计数器,下面是我个人理解的频率计数 傅里叶变换的代码: # coding=utf-8 import numpy as np from scipy.i ...
- Asp.Net Core 项目实战之权限管理系统(2) 功能及实体设计
0 Asp.Net Core 项目实战之权限管理系统(0) 无中生有 1 Asp.Net Core 项目实战之权限管理系统(1) 使用AdminLTE搭建前端 2 Asp.Net Core 项目实战之 ...
- java单例模式的实现方式
一.什么是单例模式 单例:保证一个类仅有一个实例,并提供一个访问它的全局访问点. 单例模式是一种常用的软件设计模式之一,其目的是保证整个应用中只存在类的唯一个实例. 比如我们在系统启动时,需要加载一些 ...
- FFmpeg滤镜实现区域视频增强 及 D3D实现视频播放区的拉大缩小
1.区域视频增强 FFmpeg滤镜功能十分强大,用滤镜可以实现视频的区域增强功能. 用eq滤镜就可以实现亮度.对比度.饱和度等的常用视频增强功能. 推荐两篇写得不错的博文: (1)ffmpeg综合应用 ...
- Linux下Weblogic创建域方法和步骤
Weblogic 创建域 以weblogic帐号登录(与创建域目录相对应账户) cd /home/weblogic/bea/weblogic92/common/bin 执行./config.sh进入配 ...
- Jmeter3.0发布,版本更新都更新了什么
Jmeter已发布了3.0,一个大版本的开源测试工具,加入了一些新的特性及软件的改进. Jmeter已隔10年的大版本更新 这是在过去12年里jmeter第一个大版本的更新,jmeter 2.0版本发 ...
- struts2杂记(一)——使用doubleSelect
一.前言 这段时间忙的要死,做项目,学框架,时间根本不够用,只能尽量抽出时间记录自己学过的东西. 1.1.doubleSelect 在之前学习中,我们使用过二级列表,相信很多人都理解其原理,在stru ...
- Win7系统卸载McAfee杀毒软件
方法一.用系统正常卸载程序卸载. 首先,在服务里将McAfee相关的所有服务“禁用”. 然后, Windows“控制面板”中的“添加/删除程序”卸载 McAfee Consumer 产品. 接着,到C ...
- Drupal 8.2.4安装简体中文步骤
安装的时候发现很多情况下会出现各种问题,现在写下自己安装成功的步骤: 1.首先官网下载zip安装包drupal-8.2.4.zip 2.下载官方提供的8.2.4简体中文语言包drupal-8.2.4. ...
- AlloyRenderingEngine继承
写在前面 不读文章,只对代码感兴趣可以直接跳转到这里 https://github.com/AlloyTeam/AlloyGameEngine然后star一下,多谢支持:). 前几天发了篇向ES6靠齐 ...