A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

  • The left subtree of a node contains only nodes with keys less than or equal to the node's key.
  • The right subtree of a node contains only nodes with keys greater than the node's key.
  • Both the left and right subtrees must also be binary search trees.

Insert a sequence of numbers into an initially empty binary search tree. Then you are supposed to count the total number of nodes in the lowest 2 levels of the resulting tree.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (<=1000) which is the size of the input sequence. Then given in the next line are the N integers in [-1000 1000] which are supposed to be inserted into an initially empty binary search tree.

Output Specification:

For each case, print in one line the numbers of nodes in the lowest 2 levels of the resulting tree in the format:

n1 + n2 = n

where n1 is the number of nodes in the lowest level, n2 is that of the level above, and n is the sum.

Sample Input:

9
25 30 42 16 20 20 35 -5 28

Sample Output:

2 + 4 = 6

建树,然后不断更新最大深度和次大深度,及相应点个数。
代码:
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <map>
using namespace std;
struct tree
{
int data;
tree *left,*right;
tree()
{
data = ;
left = right = NULL;
}
}*head;
int n;
int m,c1,c2;
tree *insert_(tree *r,int d,int h)
{
if(r == NULL)
{
r = new tree();
r -> data = d;
if(h > m)
{
m = h;
c2 = c1;
c1 = ;
}
else if(h == m)c1 ++;
else if(h == m - )c2 ++;
}
else if(d > r -> data)
{
r -> right = insert_(r -> right,d,h + );
}
else
{
r -> left = insert_(r -> left,d,h + );
}
return r;
}
int main()
{
int d;
scanf("%d",&n);
head = NULL;
for(int i = ;i < n;i ++)
{
scanf("%d",&d);
head = insert_(head,d,);
}
printf("%d + %d = %d",c1,c2,c1 + c2);
}

1115. Counting Nodes in a BST (30)的更多相关文章

  1. [二叉查找树] 1115. Counting Nodes in a BST (30)

    1115. Counting Nodes in a BST (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Y ...

  2. PAT Advanced 1115 Counting Nodes in a BST (30) [⼆叉树的遍历,BFS,DFS]

    题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following proper ...

  3. PAT甲题题解-1115. Counting Nodes in a BST (30)-(构建二分搜索树+dfs)

    题意:给出一个序列,构建二叉搜索树(BST),输出二叉搜索树最后两层的节点个数n1和n2,以及他们的和sum: n1 + n2 = sum 递归建树,然后再dfs求出最大层数,接着再dfs计算出最后两 ...

  4. PAT A 1115. Counting Nodes in a BST (30)【二叉排序树】

    题目:二叉排序树,统计最后两层节点个数 思路:数组格式存储,insert建树,dfs遍历 #include<cstdio> #include<iostream> #includ ...

  5. PAT (Advanced Level) 1115. Counting Nodes in a BST (30)

    简单题.统计一下即可. #include<cstdio> #include<cstring> #include<cmath> #include<vector& ...

  6. 【PAT甲级】1115 Counting Nodes in a BST (30分)(二叉查找树)

    题意: 输入一个正整数N(<=1000),接着输入N个整数([-1000,1000]),依次插入一棵初始为空的二叉排序树.输出最底层和最底层上一层的结点个数之和,例如x+y=x+y. AAAAA ...

  7. 1115 Counting Nodes in a BST (30 分)

    1115 Counting Nodes in a BST (30 分) A Binary Search Tree (BST) is recursively defined as a binary tr ...

  8. PAT甲1115 Counting Nodes in a BST【dfs】

    1115 Counting Nodes in a BST (30 分) A Binary Search Tree (BST) is recursively defined as a binary tr ...

  9. PAT 1115 Counting Nodes in a BST[构建BST]

    1115 Counting Nodes in a BST(30 分) A Binary Search Tree (BST) is recursively defined as a binary tre ...

随机推荐

  1. 将PHP 5.3.3 (cli)升级到PHP 5.6.31 (cli)

    centos默认系统安装的是php5.3 [root@sz-local1 scripts]# rpm -qa |grep phpphp-pdo-5.3.3-47.el6.x86_64php-mysql ...

  2. Window系统下MongoDB安装及远程访问

    1.编辑mongodb 安装文件夹bin\mongod.cfg 把bindIP 改为 127.0.0.1, 192.168.1.180(局域网IP) 可以参考https://blog.csdn.net ...

  3. linux服务器最大连接数

    1 受内存限制 每个tcp连接是一个打开的socket文件,因此linux服务器的最大连接数受linux操作系统单个进程同时打开的最大文件数的限制. 这个限制本质上是对单个进程内存的限制. 查看进程最 ...

  4. Channel (Java NIO)

    [正文]netty源码死磕1.3:  Java NIO Channel 1. Java NIO Channel 1.1. Java NIO Channel的特点 和老的OIO相比,通道和NIO流(非阻 ...

  5. js跨浏览器复制: ZeroClipboard

    实例结构: demo.html <script type="text/javascript" src='http://code.jquery.com/jquery.js'&g ...

  6. php字符串操作: 去掉UTF-16的空格

    $s = json_encode($s); $s = str_replace('\u00a0','',$s); $s = str_replace('\u3000','',$s); $s = str_r ...

  7. mysql中子查询更新,得用别名表

    通过查出最大id,来更新记录 update order set status = 'xx' where id in (select v.id from (select max(id) id from ...

  8. Java内部类(转发:)

    内部类是指在一个外部类的内部再定义一个类.类名不需要和文件夹相同. 内部类分为: 成员内部类.局部内部类.静态嵌套类.匿名内部类 . 1.成员内部类 成员内部类是最普通的内部类,它的定义为位于另一个类 ...

  9. activiti基础--2----------------------(流程定义)

    Deployment 部署对象 1.一次部署的多个文件信息,对于不需要的流程可以删除和修改 2.对应的表 act_re_deployment #部署对象表 act_re_procdef #流程定义表 ...

  10. Java进阶学习:JSON解析利器JackSon

    Java:JSON解析利器JackSon JackSon基础 1.Maven项目引入 <!-- https://mvnrepository.com/artifact/org.codehaus.j ...