1115. Counting Nodes in a BST (30)
A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than or equal to the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Insert a sequence of numbers into an initially empty binary search tree. Then you are supposed to count the total number of nodes in the lowest 2 levels of the resulting tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=1000) which is the size of the input sequence. Then given in the next line are the N integers in [-1000 1000] which are supposed to be inserted into an initially empty binary search tree.
Output Specification:
For each case, print in one line the numbers of nodes in the lowest 2 levels of the resulting tree in the format:
n1 + n2 = n
where n1 is the number of nodes in the lowest level, n2 is that of the level above, and n is the sum.
Sample Input:
9
25 30 42 16 20 20 35 -5 28
Sample Output:
2 + 4 = 6
建树,然后不断更新最大深度和次大深度,及相应点个数。
代码:
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <map>
using namespace std;
struct tree
{
int data;
tree *left,*right;
tree()
{
data = ;
left = right = NULL;
}
}*head;
int n;
int m,c1,c2;
tree *insert_(tree *r,int d,int h)
{
if(r == NULL)
{
r = new tree();
r -> data = d;
if(h > m)
{
m = h;
c2 = c1;
c1 = ;
}
else if(h == m)c1 ++;
else if(h == m - )c2 ++;
}
else if(d > r -> data)
{
r -> right = insert_(r -> right,d,h + );
}
else
{
r -> left = insert_(r -> left,d,h + );
}
return r;
}
int main()
{
int d;
scanf("%d",&n);
head = NULL;
for(int i = ;i < n;i ++)
{
scanf("%d",&d);
head = insert_(head,d,);
}
printf("%d + %d = %d",c1,c2,c1 + c2);
}
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