杭电acm 1039题

这道题也比较简单，写三个函数判断三个条件即可.....

但是开始时我按照已经注释掉的提交，居然提示WA，我百思不得其解，后改成上面的判断式就可以了，求高手解答....

 #include "iostream"

 using namespace std;

 #define Max 21
 int Function1(char *p,int len);
 int Function2(char *p,int len);
 int Function3(char *p,int len);
 int vowel(char p);
 int main(void)
 {
     char letters[Max];
     int len;
     int condition_1=,condition_2=,condition_3=;
     while(cin>>letters)
     {
         if(!strcmp(letters,"end"))
             break;
         len=strlen(letters);
         condition_1=Function1(letters,len);
         condition_2=Function2(letters,len);
         condition_3=Function3(letters,len);
         if(condition_1&&condition_2&&condition_3)
             cout<<"<"<<letters<<">"<<" is acceptable."<<endl;
         else
             cout<<"<"<<letters<<">"<<" is not acceptable."<<endl;
     /*    if(condition_1==1)
         {
             condition_2=Function2(letters,len);
             if(condition_2==1)
             {
                 condition_3=Function3(letters,len);
                 if(condition_3==1)
                     cout<<"<"<<letters<<">"<<" is acceptable."<<endl;
                 else cout<<"<"<<letters<<">"<<" is not acceptable."<<endl;
             }
             else cout<<"<"<<letters<<">"<<" is not acceptable."<<endl;
         }
         else cout<<"<"<<letters<<">"<<" is not acceptable."<<endl;*/
     }
     return ;
 }

 int Function1(char *p,int len)
 {
     for(int i=;i<len;i++)
     {
         if(p[i]=='a'||p[i]=='e'||p[i]=='i'||p[i]=='o'||p[i]=='u')
             return ;
     }
     return ;
 }
 int Function2(char *p,int len)
 {
     for(int i=;i<len;i++)
     {
         if(((i+)<len)&&(vowel(p[i]))&&(vowel(p[i+]))&&(vowel(p[i+])))
             return ;
         else if(((i+)<len)&&(!vowel(p[i]))&&(!vowel(p[i+]))&&(!vowel(p[i+])))
             return ;
     }
     return ;
 }
 int Function3(char *p,int len)
 {
     char flag;
     for(int i=;i<len;i++)
     {
         flag=p[i];
         if(((i+)<len)&&(p[i+]==flag)&&(flag!='e')&&(flag!='o'))
             return ;
     }
     return ;
 }

 int vowel(char p)
 {
     if(p=='a'||p=='e'||p=='i'||p=='o'||p=='u')
         return ;
     else return ;
 }