蓝桥网试题 java 基础练习 矩形面积交

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思路见锦囊2

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算法

 import java.util.Scanner;
 public class Main {
     public static void main(String[] args) {
         Scanner sc = new Scanner(System.in);
         double[] x = new double[4];
         double[] y = new double[4];
         double[] z = new double[4];
         for(int i=0;i<4;i++){
             x[i] = sc.nextDouble();
             y[i] = sc.nextDouble();
         }
         z[0] = Math.max(Math.min(x[0], x[1]),Math.min(x[2], x[3])); //x1
         z[1] = Math.min(Math.max(x[0], x[1]),Math.max(x[2], x[3])); //x2

         z[2] = Math.max(Math.min(y[0], y[1]),Math.min(y[2], y[3])); //y1
         z[3] = Math.min(Math.max(y[0], y[1]),Math.max(y[2], y[3])); //y2
         if(z[0]<z[1]&&z[2]<z[3])
             System.out.printf("%.2f\n",(z[1]-z[0])*(z[3]-z[2]));
         else
             System.out.println("0.00");
     }
 }