FB面经 Prepare: All Palindromic Substrings
Given a string, calculate how many substring is palindrome. Ignore non-char characters. Ignore case; Ex: "A@,b123a", equals "Aba", should output 4: "A", "b", "a", "Aba"
Spread from center: Like LC 5: longest palindromic substring
package fb;
public class Palindrome {
public int countSubStr(String input) {
if (input==null || input.length()==0) return 0;
int res = 0;
for (int i=0; i<input.length(); i++) {
if (!isAlpha(input, i)) continue;
res += helper(input, i, i);
if (i < input.length()-1) res += helper(input, i, i+1);
}
return res;
}
public int helper(String s, int l, int r) {
int res = 0;
while (l>=0 && r<s.length()) {
while (l>=0 && !isAlpha(s, l)) l--;
while (r<s.length() && !isAlpha(s, r)) r++;
if (l<0 || r>=s.length() || !isSame(s, l, r)) break;
else {
res++;
l--;
r++;
}
}
return res;
}
public boolean isAlpha(String s, int i) {
char c = s.charAt(i);
if (c>='a' && c<='z' || c>='A' && c<='Z') return true;
return false;
}
public boolean isSame(String s, int l, int r) {
char ll = s.charAt(l);
char rr = s.charAt(r);
ll = Character.isUpperCase(ll)? (char)(ll-'A'+'a') : ll;
rr = Character.isUpperCase(rr)? (char)(rr-'A'+'a') : rr;
return ll==rr;
}
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Palindrome sol = new Palindrome();
String input = "A@,b123a";
//String input = "Aba";
int res = sol.countSubStr(input);
System.out.println(res);
}
}
FB面经 Prepare: All Palindromic Substrings的更多相关文章
- [LeetCode] Palindromic Substrings 回文子字符串
Given a string, your task is to count how many palindromic substrings in this string. The substrings ...
- [Swift]LeetCode647. 回文子串 | Palindromic Substrings
Given a string, your task is to count how many palindromic substrings in this string. The substrings ...
- 647. Palindromic Substrings
Given a string, your task is to count how many palindromic substrings in this string. The substrings ...
- Leetcode 647. Palindromic Substrings
Given a string, your task is to count how many palindromic substrings in this string. The substrings ...
- LeetCode——Palindromic Substrings
Question Given a string, your task is to count how many palindromic substrings in this string. The s ...
- 647. Palindromic Substrings 互文的子字符串
[抄题]: Given a string, your task is to count how many palindromic substrings in this string. The subs ...
- 【Leetcode】647. Palindromic Substrings
Description Given a string, your task is to count how many palindromic substrings in this string. Th ...
- [LeetCode] 647. Palindromic Substrings 回文子字符串
Given a string, your task is to count how many palindromic substrings in this string. The substrings ...
- LeetCode 647. 回文子串(Palindromic Substrings)
647. 回文子串 647. Palindromic Substrings 题目描述 给定一个字符串,你的任务是计算这个字符串中有多少个回文子串. 具有不同开始位置或结束位置的子串,即使是由相同的字符 ...
随机推荐
- 转:loadruner报错:Step download timeout(120 seconds)的一个解决方法
一个网友问了我一个问题如下:loadruner报错:Error -27728: Step download timeout (120 seconds) 如何解决语法检查通过,但是在并发执行一个查询时候 ...
- NYOJ 925 国王的烦恼
从最后一天开始往前加边. 同一天的边同时加到图上,加完之后检查集合数量是否和没加之前有变化. 有变化的话,答案就+1. #include<cstdio> #include <iost ...
- Ubuntu VPN PPTP 连接要选上这个啊
选上MPPE点到点加密..
- Javascript模块化编程:AMD规范及require.js用法【转】 - loheonly的笔记 - 前端网(W3Cfuns)
http://www.w3cfuns.com/blog-5425789-5399326.html
- 剑指offer之有序二维数组查找
大多数人注意到元素是行列有序的,会马上想到对每行(或列)进行二分查找,每行(或列)需要logN时间,N行(或列)共需要NlogN时间,很容易写出如下代码 1 2 3 4 5 6 7 8 9 10 11 ...
- Servlet程序开发-- 过滤器
3种servlet:简单Servlet,过滤Servlet,监听Servlet 1. 简单Servlet:是作为一种程序所必须的开发结构保存下来的. 2. 过滤Servlet:过滤器使用的不是Http ...
- [jQueryUI] – Chosen:select下拉选择框美化插件及问题
Chosen 是一个支持jquery的select下拉框美化插件,它能让丑陋的.很长的select选择框变的更好看.更方便.不仅如此,它更扩展了select,增加了自动筛选的功能.它可对列表进行分组, ...
- They Are Everywhere
They Are Everywhere Sergei B., the young coach of Pokemons, has found the big house which consists o ...
- CentOS6.5 安装ntopng-1.2.0
0.准备工作 安装libpcap:最好源码安装. yum install -y libpcap* 安装redis yum install -y redis* 1.安装 tar -zxvf ntopng ...
- spider JAVA如何判断网页编码 (转载)
原文链接 http://www.cnblogs.com/nanxin/archive/2013/03/27/2984320.html 前言 最近做一个搜索项目,需要爬取很多网站获取需要的信息.在爬取网 ...